A proton of mass 1.67x10^27 kg, moves in a circle in the plane perpendicular to a uniform magnetic field of magnitude 1.8T. The radius of curvature is 3.0cm. what is the speed of the proton?

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To speed things up, the equation is \[v=qBr/m\]

q looks like the charge (in Coulombs perhaps?) of the proton, but i'm not entirely sure

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