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anonymous
 4 years ago
pset3 problem1. sos. i can't make recursive one
can anybody give me some hint please?
anonymous
 4 years ago
pset3 problem1. sos. i can't make recursive one can anybody give me some hint please?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i just have got an answer!

maitre_kaio
 4 years ago
Best ResponseYou've already chosen the best response.4The two functions should return the number of occurrences of key in target. You can check my version here: http://codepad.org/qz73jpja I also joined two diagrams to help you visualize the code. Let's review first the code of your iterative version. My first objection is that you always return None, even if you print occurrences when you find them. You should have a variable which counts how many times you find the key. Now you iterate over the target, starting with position 0, if you find the key at position n, increment your counter and search again starting at position n+1. As soon as you don't find the key, return the number of occurrences you have found. Now let's look at the recursive version. You did pretty well and almost found the answer, since you call the same function with a shorter target (hence it is a simplified version of the same problem). You should only ask yourself: what do I want to return when I don't find the key > you should return 0. And when I find the key? > 1 + return from the shorter target. I hope I made it clear, but let me know if it is not enough !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0very helpful advice! thank you!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maitre_kao. nice job. elegant. i like the way you increment directly in the return statement.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here is another variation http://dpaste.com/685648/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0bwCA. very cool and concise. didn't know about "not in"
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