Mrs.Math101
Simplify i231 where i is the imaginary unit and is defined as: i = sqrt(1).



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kirihara
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I think the answer would be 1

kirihara
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yup 1

anonymous
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no i do not think it is 1

anonymous
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\[i^{231}\] take the integer remainder when dividing 231 by 4 and you get 3 (since 4 divides 228 evenly)
therefore
\[i^{231}=i^3=i\]

anonymous
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\[i^0=1,i^1=i,i^2=1,i^3=i,i^4=1, ...\]

wasiqss
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answer is indeed i