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pokemon23

helping with radicals

  • 2 years ago
  • 2 years ago

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  1. NotTim
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    Specify?

    • 2 years ago
  2. pokemon23
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    |dw:1326247869818:dw|

    • 2 years ago
  3. nobody1
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    4sqrt.5

    • 2 years ago
  4. Akshay_Budhkar
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    hey pokemon, try it yourself, thats how you will learnn , i will guide you

    • 2 years ago
  5. NotTim
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    The whole point of this website actually...

    • 2 years ago
  6. Akshay_Budhkar
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    u trying it man?

    • 2 years ago
  7. pokemon23
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    ok

    • 2 years ago
  8. pokemon23
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    |dw:1326248463156:dw|

    • 2 years ago
  9. SamIam
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    hey i am here

    • 2 years ago
  10. pokemon23
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    ok

    • 2 years ago
  11. pokemon23
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    so far correct?

    • 2 years ago
  12. Akshay_Budhkar
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    ok hello again pokemon

    • 2 years ago
  13. pokemon23
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    hello?

    • 2 years ago
  14. Akshay_Budhkar
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    no check your \[1/2 \times \sqrt 20\]

    • 2 years ago
  15. Akshay_Budhkar
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    what is \[\sqrt 20 = \sqrt {4 \times 5}\]

    • 2 years ago
  16. Akshay_Budhkar
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    now you know\[\sqrt 4 =2\]

    • 2 years ago
  17. Akshay_Budhkar
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    so \[\sqrt 20 = 2 \times \sqrt 5\]

    • 2 years ago
  18. SamIam
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    hey akshay is helping u out. He is good

    • 2 years ago
  19. Akshay_Budhkar
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    but you want \[1/2 \sqrt 20 = \sqrt 5\]

    • 2 years ago
  20. Akshay_Budhkar
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    you fine till here man?

    • 2 years ago
  21. Akshay_Budhkar
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    Hey samlam thanks hehe

    • 2 years ago
  22. pokemon23
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    so lost?

    • 2 years ago
  23. Akshay_Budhkar
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    ok what is that you don't get?

    • 2 years ago
  24. pokemon23
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    so the square root of 20 is the product of 5*4

    • 2 years ago
  25. Akshay_Budhkar
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    square root of 20 is square root of 4*5

    • 2 years ago
  26. SamIam
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    |dw:1326249125280:dw|

    • 2 years ago
  27. SamIam
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    |dw:1326249164510:dw| did u get that?

    • 2 years ago
  28. Akshay_Budhkar
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    you fine with this.?

    • 2 years ago
  29. Akshay_Budhkar
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    \[\sqrt ab = \sqrt a \times \sqrt b\]

    • 2 years ago
  30. pokemon23
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    yes i got that

    • 2 years ago
  31. pokemon23
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    now

    • 2 years ago
  32. Akshay_Budhkar
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    ok now do the next one

    • 2 years ago
  33. Akshay_Budhkar
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    \[\sqrt 45\]

    • 2 years ago
  34. Akshay_Budhkar
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    go step by step

    • 2 years ago
  35. pokemon23
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    |dw:1326249246307:dw|

    • 2 years ago
  36. Akshay_Budhkar
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    no

    • 2 years ago
  37. Akshay_Budhkar
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    why are they two roots?

    • 2 years ago
  38. Akshay_Budhkar
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    *square roots

    • 2 years ago
  39. Akshay_Budhkar
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    \[\sqrt 45 = \sqrt 9 \times \sqrt 5\]

    • 2 years ago
  40. Akshay_Budhkar
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    is that what you mean?

    • 2 years ago
  41. pokemon23
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    yes

    • 2 years ago
  42. Akshay_Budhkar
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    ok go ahead :D

    • 2 years ago
  43. pokemon23
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    |dw:1326249569591:dw|

    • 2 years ago
  44. SamIam
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    how is it going pokeman?

    • 2 years ago
  45. Akshay_Budhkar
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    Go ahead yea. solve the whole thing now

    • 2 years ago
  46. pokemon23
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    its going great i supposed

    • 2 years ago
  47. SamIam
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    YAHOO :DDDDDDDDDDDDD

    • 2 years ago
  48. Akshay_Budhkar
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    ok pokemon i am still here :D go ahead

    • 2 years ago
  49. SamIam
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    bye pokeman gonna go study see u around

    • 2 years ago
  50. pokemon23
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    ok

    • 2 years ago
  51. pokemon23
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    |dw:1326250193101:dw|

    • 2 years ago
  52. Akshay_Budhkar
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    ok it is something like this \[1/2 \sqrt 20 + \sqrt 45\] =\[\sqrt 5 + 3 \sqrt 5\] =\[4 \sqrt 5\]

    • 2 years ago
  53. pokemon23
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    what happen to the 1/2?

    • 2 years ago
  54. SamIam
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    akshay u r awesome xD

    • 2 years ago
  55. pokemon23
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    how did you get |dw:1326250676815:dw|

    • 2 years ago
  56. Akshay_Budhkar
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    ok it is \[1/2 \sqrt 20 \] Now you have \[\sqrt 20 = 2 \sqrt 5\] so that multiplied by 1/2 gives you \[\sqrt 5\]

    • 2 years ago
  57. Akshay_Budhkar
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    and for \[\sqrt 45 = 3 \sqrt 5\]

    • 2 years ago
  58. Akshay_Budhkar
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    LOL samlan , i am not awesome ..

    • 2 years ago
  59. SamIam
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    ohhh don't blush try to accept the compliment

    • 2 years ago
  60. Akshay_Budhkar
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    thanks hehe :D

    • 2 years ago
  61. pokemon23
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    doesn't |dw:1326250913607:dw|

    • 2 years ago
  62. Akshay_Budhkar
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    yes that is what i got.. \[4 \sqrt 5\]

    • 2 years ago
  63. pokemon23
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    i got more questions willing to help me

    • 2 years ago
  64. SamIam
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    i heard hero got married LOL

    • 2 years ago
  65. pokemon23
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    seriously?

    • 2 years ago
  66. Akshay_Budhkar
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    Anytime pokemon i told you i never tell no to questions, but its kinda late here, i got some 15 minutes

    • 2 years ago
  67. SamIam
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    i dont to kaka LOL

    • 2 years ago
  68. Akshay_Budhkar
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    ??

    • 2 years ago
  69. Akshay_Budhkar
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    u kidding?

    • 2 years ago
  70. Akshay_Budhkar
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    kaka?

    • 2 years ago
  71. SamIam
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    there was a party on twiddla

    • 2 years ago
  72. SamIam
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    i missed out :(

    • 2 years ago
  73. pokemon23
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    ok thanks

    • 2 years ago
  74. pokemon23
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    |dw:1326251216009:dw|

    • 2 years ago
  75. SamIam
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    oh u gotta first do foil Arrrrrgggghhhh

    • 2 years ago
  76. SamIam
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    call hero to help u

    • 2 years ago
  77. pokemon23
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    |dw:1326251317018:dw|

    • 2 years ago
  78. pokemon23
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    isn't hero busy?

    • 2 years ago
  79. SamIam
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    let me ask him

    • 2 years ago
  80. pokemon23
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    I don't want to bother him

    • 2 years ago
  81. Akshay_Budhkar
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    ok go step by step, open the brackets

    • 2 years ago
  82. pokemon23
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    do we need to used foil?

    • 2 years ago
  83. Akshay_Budhkar
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    (a+b)(c+d)= ac + ad + bc + bd

    • 2 years ago
  84. pokemon23
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    ok thanks

    • 2 years ago
  85. Akshay_Budhkar
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    so use that in the thing above

    • 2 years ago
  86. pokemon23
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    |dw:1326251886970:dw|

    • 2 years ago
  87. Akshay_Budhkar
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    yes

    • 2 years ago
  88. pokemon23
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    so when we multiply the answer is 3*7=|dw:1326251983779:dw|

    • 2 years ago
  89. Akshay_Budhkar
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    ok it is \[3 \times \sqrt 7 = 3 \sqrt 7\]

    • 2 years ago
  90. Akshay_Budhkar
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    neither of the above u wrote is correct

    • 2 years ago
  91. pokemon23
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    |dw:1326252144798:dw|

    • 2 years ago
  92. Akshay_Budhkar
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    perfect

    • 2 years ago
  93. Akshay_Budhkar
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    thats it?

    • 2 years ago
  94. pokemon23
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    |dw:1326252489033:dw|

    • 2 years ago
  95. Akshay_Budhkar
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    oh no you have to ADD them

    • 2 years ago
  96. pokemon23
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    |dw:1326252535016:dw|

    • 2 years ago
  97. Akshay_Budhkar
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    sorry pokemon my eyes are dropping.. i got work tomorrow early.. i will be back tomorrow evening.. till that time you can take somewlse's help, i will help you tomorrow, sorry again

    • 2 years ago
  98. Akshay_Budhkar
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    u here?

    • 2 years ago
  99. pokemon23
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    ok

    • 2 years ago
  100. pokemon23
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    no problem

    • 2 years ago
  101. Akshay_Budhkar
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    have a great day ahead! and meet you tomorrow.. we need to work a bit faster from now ok?

    • 2 years ago
  102. pokemon23
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    yes

    • 2 years ago
  103. pokemon23
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    am I correct?

    • 2 years ago
  104. Mrs.Math101
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    1/2 \sqrt 20 = \sqrt 5

    • 2 years ago
  105. pokemon23
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    for the|dw:1326254978405:dw|

    • 2 years ago
  106. pokemon23
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    my answer is |dw:1326255046497:dw|

    • 2 years ago
  107. Mrs.Math101
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    yes

    • 2 years ago
  108. pokemon23
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    yipeeeeeeeeeeeeeeeeeeee

    • 2 years ago
  109. pokemon23
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    rationalize the denominator and simplify the resulting fraction.

    • 2 years ago
  110. pokemon23
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    |dw:1326255280427:dw|

    • 2 years ago
  111. pokemon23
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    for this question mrs.math

    • 2 years ago
  112. pokemon23
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    |dw:1326255332662:dw|

    • 2 years ago
  113. Mrs.Math101
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    yes that is correct

    • 2 years ago
  114. pokemon23
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    would the answer be 1

    • 2 years ago
  115. pokemon23
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    my mistake 7

    • 2 years ago
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