pokemon23
  • pokemon23
helping with radicals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
NotTim
  • NotTim
Specify?
pokemon23
  • pokemon23
|dw:1326247869818:dw|
anonymous
  • anonymous
4sqrt.5

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More answers

Akshay_Budhkar
  • Akshay_Budhkar
hey pokemon, try it yourself, thats how you will learnn , i will guide you
NotTim
  • NotTim
The whole point of this website actually...
Akshay_Budhkar
  • Akshay_Budhkar
u trying it man?
pokemon23
  • pokemon23
ok
pokemon23
  • pokemon23
|dw:1326248463156:dw|
SamIam
  • SamIam
hey i am here
pokemon23
  • pokemon23
ok
pokemon23
  • pokemon23
so far correct?
Akshay_Budhkar
  • Akshay_Budhkar
ok hello again pokemon
pokemon23
  • pokemon23
hello?
Akshay_Budhkar
  • Akshay_Budhkar
no check your \[1/2 \times \sqrt 20\]
Akshay_Budhkar
  • Akshay_Budhkar
what is \[\sqrt 20 = \sqrt {4 \times 5}\]
Akshay_Budhkar
  • Akshay_Budhkar
now you know\[\sqrt 4 =2\]
Akshay_Budhkar
  • Akshay_Budhkar
so \[\sqrt 20 = 2 \times \sqrt 5\]
SamIam
  • SamIam
hey akshay is helping u out. He is good
Akshay_Budhkar
  • Akshay_Budhkar
but you want \[1/2 \sqrt 20 = \sqrt 5\]
Akshay_Budhkar
  • Akshay_Budhkar
you fine till here man?
Akshay_Budhkar
  • Akshay_Budhkar
Hey samlam thanks hehe
pokemon23
  • pokemon23
so lost?
Akshay_Budhkar
  • Akshay_Budhkar
ok what is that you don't get?
pokemon23
  • pokemon23
so the square root of 20 is the product of 5*4
Akshay_Budhkar
  • Akshay_Budhkar
square root of 20 is square root of 4*5
SamIam
  • SamIam
|dw:1326249125280:dw|
SamIam
  • SamIam
|dw:1326249164510:dw| did u get that?
Akshay_Budhkar
  • Akshay_Budhkar
you fine with this.?
Akshay_Budhkar
  • Akshay_Budhkar
\[\sqrt ab = \sqrt a \times \sqrt b\]
pokemon23
  • pokemon23
yes i got that
pokemon23
  • pokemon23
now
Akshay_Budhkar
  • Akshay_Budhkar
ok now do the next one
Akshay_Budhkar
  • Akshay_Budhkar
\[\sqrt 45\]
Akshay_Budhkar
  • Akshay_Budhkar
go step by step
pokemon23
  • pokemon23
|dw:1326249246307:dw|
Akshay_Budhkar
  • Akshay_Budhkar
no
Akshay_Budhkar
  • Akshay_Budhkar
why are they two roots?
Akshay_Budhkar
  • Akshay_Budhkar
*square roots
Akshay_Budhkar
  • Akshay_Budhkar
\[\sqrt 45 = \sqrt 9 \times \sqrt 5\]
Akshay_Budhkar
  • Akshay_Budhkar
is that what you mean?
pokemon23
  • pokemon23
yes
Akshay_Budhkar
  • Akshay_Budhkar
ok go ahead :D
pokemon23
  • pokemon23
|dw:1326249569591:dw|
SamIam
  • SamIam
how is it going pokeman?
Akshay_Budhkar
  • Akshay_Budhkar
Go ahead yea. solve the whole thing now
pokemon23
  • pokemon23
its going great i supposed
SamIam
  • SamIam
YAHOO :DDDDDDDDDDDDD
Akshay_Budhkar
  • Akshay_Budhkar
ok pokemon i am still here :D go ahead
SamIam
  • SamIam
bye pokeman gonna go study see u around
pokemon23
  • pokemon23
ok
pokemon23
  • pokemon23
|dw:1326250193101:dw|
Akshay_Budhkar
  • Akshay_Budhkar
ok it is something like this \[1/2 \sqrt 20 + \sqrt 45\] =\[\sqrt 5 + 3 \sqrt 5\] =\[4 \sqrt 5\]
pokemon23
  • pokemon23
what happen to the 1/2?
SamIam
  • SamIam
akshay u r awesome xD
pokemon23
  • pokemon23
how did you get |dw:1326250676815:dw|
Akshay_Budhkar
  • Akshay_Budhkar
ok it is \[1/2 \sqrt 20 \] Now you have \[\sqrt 20 = 2 \sqrt 5\] so that multiplied by 1/2 gives you \[\sqrt 5\]
Akshay_Budhkar
  • Akshay_Budhkar
and for \[\sqrt 45 = 3 \sqrt 5\]
Akshay_Budhkar
  • Akshay_Budhkar
LOL samlan , i am not awesome ..
SamIam
  • SamIam
ohhh don't blush try to accept the compliment
Akshay_Budhkar
  • Akshay_Budhkar
thanks hehe :D
pokemon23
  • pokemon23
doesn't |dw:1326250913607:dw|
Akshay_Budhkar
  • Akshay_Budhkar
yes that is what i got.. \[4 \sqrt 5\]
pokemon23
  • pokemon23
i got more questions willing to help me
SamIam
  • SamIam
i heard hero got married LOL
pokemon23
  • pokemon23
seriously?
Akshay_Budhkar
  • Akshay_Budhkar
Anytime pokemon i told you i never tell no to questions, but its kinda late here, i got some 15 minutes
SamIam
  • SamIam
i dont to kaka LOL
Akshay_Budhkar
  • Akshay_Budhkar
??
Akshay_Budhkar
  • Akshay_Budhkar
u kidding?
Akshay_Budhkar
  • Akshay_Budhkar
kaka?
SamIam
  • SamIam
there was a party on twiddla
SamIam
  • SamIam
i missed out :(
pokemon23
  • pokemon23
ok thanks
pokemon23
  • pokemon23
|dw:1326251216009:dw|
SamIam
  • SamIam
oh u gotta first do foil Arrrrrgggghhhh
SamIam
  • SamIam
call hero to help u
pokemon23
  • pokemon23
|dw:1326251317018:dw|
pokemon23
  • pokemon23
isn't hero busy?
SamIam
  • SamIam
let me ask him
pokemon23
  • pokemon23
I don't want to bother him
Akshay_Budhkar
  • Akshay_Budhkar
ok go step by step, open the brackets
pokemon23
  • pokemon23
do we need to used foil?
Akshay_Budhkar
  • Akshay_Budhkar
(a+b)(c+d)= ac + ad + bc + bd
pokemon23
  • pokemon23
ok thanks
Akshay_Budhkar
  • Akshay_Budhkar
so use that in the thing above
pokemon23
  • pokemon23
|dw:1326251886970:dw|
Akshay_Budhkar
  • Akshay_Budhkar
yes
pokemon23
  • pokemon23
so when we multiply the answer is 3*7=|dw:1326251983779:dw|
Akshay_Budhkar
  • Akshay_Budhkar
ok it is \[3 \times \sqrt 7 = 3 \sqrt 7\]
Akshay_Budhkar
  • Akshay_Budhkar
neither of the above u wrote is correct
pokemon23
  • pokemon23
|dw:1326252144798:dw|
Akshay_Budhkar
  • Akshay_Budhkar
perfect
Akshay_Budhkar
  • Akshay_Budhkar
thats it?
pokemon23
  • pokemon23
|dw:1326252489033:dw|
Akshay_Budhkar
  • Akshay_Budhkar
oh no you have to ADD them
pokemon23
  • pokemon23
|dw:1326252535016:dw|
Akshay_Budhkar
  • Akshay_Budhkar
sorry pokemon my eyes are dropping.. i got work tomorrow early.. i will be back tomorrow evening.. till that time you can take somewlse's help, i will help you tomorrow, sorry again
Akshay_Budhkar
  • Akshay_Budhkar
u here?
pokemon23
  • pokemon23
ok
pokemon23
  • pokemon23
no problem
Akshay_Budhkar
  • Akshay_Budhkar
have a great day ahead! and meet you tomorrow.. we need to work a bit faster from now ok?
pokemon23
  • pokemon23
yes
pokemon23
  • pokemon23
am I correct?
anonymous
  • anonymous
1/2 \sqrt 20 = \sqrt 5
pokemon23
  • pokemon23
for the|dw:1326254978405:dw|
pokemon23
  • pokemon23
my answer is |dw:1326255046497:dw|
anonymous
  • anonymous
yes
pokemon23
  • pokemon23
yipeeeeeeeeeeeeeeeeeeee
pokemon23
  • pokemon23
rationalize the denominator and simplify the resulting fraction.
pokemon23
  • pokemon23
|dw:1326255280427:dw|
pokemon23
  • pokemon23
for this question mrs.math
pokemon23
  • pokemon23
|dw:1326255332662:dw|
anonymous
  • anonymous
yes that is correct
pokemon23
  • pokemon23
would the answer be 1
pokemon23
  • pokemon23
my mistake 7

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