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 3 years ago
how do you do these?
I got 2,3, and 4. But I NEED #1
If you could give me all of them that'd be great
 3 years ago
how do you do these? I got 2,3, and 4. But I NEED #1 If you could give me all of them that'd be great

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shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.2so sin x=8/17. cos x=sqrt(1xin^2 x)=sqrt(164/289)=sqrt(225/289)=15/17. as it is given cos x is negative. so, sec x=1/cos x=17/15

alexislovesyou5502
 3 years ago
Best ResponseYou've already chosen the best response.0have u figured it out yet mister?

hooooooooooope
 3 years ago
Best ResponseYou've already chosen the best response.0so the overall answer for #1 is ?

shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.2Did you understand the method or not??

alexislovesyou5502
 3 years ago
Best ResponseYou've already chosen the best response.0Look all u have to do is go back to where that person explained it to you and try harder to under stand it!

shankvee\
 3 years ago
Best ResponseYou've already chosen the best response.2Do you know sin^2 x + cos ^2 x=1?

hooooooooooope
 3 years ago
Best ResponseYou've already chosen the best response.0I don't understand what the final answer is for #1. Is it (17/15) ?

hooooooooooope
 3 years ago
Best ResponseYou've already chosen the best response.0For the rest I have: 2) sin(arctan(1)) 3) 5.196152 4) 8.9644 are those right?

kennethreynold8
 3 years ago
Best ResponseYou've already chosen the best response.0#1 \[\cos \Theta\] =15/17 \[\sec \Theta\] =17/15 #2 \[\sin(\tan^{1} (1)=\] \[\sin 45 =\] \[\sqrt{2}/2\] #3 \[6(1/\sqrt{3})2(\sqrt{3}/2)\] \[6(\sqrt{3}/3) + \sqrt{3}\] \[2\sqrt{3} + \sqrt{3}\] \[3\sqrt{3}\] #4 tan 35 = a/10 tan 62 = b/10 a = 0.7002*10 b=1.8807*10 a = 7.002 b = 18.807 Distance between towns is: 18.8077.002 ans: 11.805

hooooooooooope
 3 years ago
Best ResponseYou've already chosen the best response.0So at the bottom to find the URL i keep doing it but it won't work
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