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Ayed
I need help with this f(x)=2x^2+8x-8
graph each parabola and give its vertex,axis,x-intercepts,and y-intercept.
x intercept set y=0 y intercept set x = 0 Vortex can be found by using the equation -(2b/a) = x where a = 2 b = +8 in this case, to find the y value sub the x value you get from that equation and you have your vortex To graph just make a table of x values to from -3 to +3 and sub them into the function to see what y values you get then graph the points and intercepts
use quadric formula solve\[\frac{-b \pm \sqrt{b^2-(4*a*c)}}{2*a}\]a=2 b=8 c=-8
You would use the quadratic formula to solve the x intercepts
also whenever dealing with the quadratic formula solve what is in the radical first, dont just punch all that stuff into your calculator
How i can write ± in my calculator???
solve it algebraically don't use your calculator
Finally I got it Thanks guys