anonymous
  • anonymous
true or falsee? y = 11^x is written as log11y = x.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Definition of Log Log(x) = y b^(y) = x
anonymous
  • anonymous
Take the log at base 11 of both sides of y = 11^(x) \[\log_{11} (y) = x\]
anonymous
  • anonymous
The \[\log_{11} \] will cancel out on one side leaving x

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anonymous
  • anonymous
the other side will be log_11(y) so yes if it is log11(y) than it is correct

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