beth12345
  • beth12345
how to find the value of 'X' when x^2-8x=8?
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Mimi_x3
  • Mimi_x3
\[x^2-8x-8 = 0 \] Use the quadratic formula: \[\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \] \[a = 1 , b=-8 , c = -8\] And sub it in.
beth12345
  • beth12345
ok thanx
anonymous
  • anonymous
use the quadratic formula. \[(-b \pm \sqrt{b ^{2} -4ac}) /2a \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
x^2-8x=8 x(x-8)=8 or x=2 and x-8=4 x=2, x=12
beth12345
  • beth12345
thank you, i never thouht of it that way but i can see how it works :)
anonymous
  • anonymous
but this solution is wrong
beth12345
  • beth12345
?
anonymous
  • anonymous
x=2, x=12 is a wrong solution
Mimi_x3
  • Mimi_x3
Completing the square would work as well. But using the quadratic formula is easier.
beth12345
  • beth12345
i thought it would be like (2)[(12)-8]=8?
beth12345
  • beth12345
oh ok, mimi, i did the formula and got 4+or-2root6, is that right?
anonymous
  • anonymous
Ravi, in case you were wondering why it's wrong it's because you must factorise the equation equal to 0. 8 has an infinite number of non-integer factors, so you can't solve. 0, on the other hand, must have the value of a factor as 0.
beth12345
  • beth12345
thanks samarilli, i see now why it's not the same answer as when i use the formula
Mimi_x3
  • Mimi_x3
Well, i got \[\frac{-8\pm\sqrt{96}}{2} \]
anonymous
  • anonymous
thanks Simarilli

Looking for something else?

Not the answer you are looking for? Search for more explanations.