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Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[x^28x8 = 0 \] Use the quadratic formula: \[\frac{(b)\pm\sqrt{(b)^{2}4(a)(c)}}{2(a)} \] \[a = 1 , b=8 , c = 8\] And sub it in.
 2 years ago

Mohammad_Asad_Ali Group TitleBest ResponseYou've already chosen the best response.0
use the quadratic formula. \[(b \pm \sqrt{b ^{2} 4ac}) /2a \]
 2 years ago

ravi623 Group TitleBest ResponseYou've already chosen the best response.0
x^28x=8 x(x8)=8 or x=2 and x8=4 x=2, x=12
 2 years ago

beth12345 Group TitleBest ResponseYou've already chosen the best response.0
thank you, i never thouht of it that way but i can see how it works :)
 2 years ago

ravi623 Group TitleBest ResponseYou've already chosen the best response.0
but this solution is wrong
 2 years ago

ravi623 Group TitleBest ResponseYou've already chosen the best response.0
x=2, x=12 is a wrong solution
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Completing the square would work as well. But using the quadratic formula is easier.
 2 years ago

beth12345 Group TitleBest ResponseYou've already chosen the best response.0
i thought it would be like (2)[(12)8]=8?
 2 years ago

beth12345 Group TitleBest ResponseYou've already chosen the best response.0
oh ok, mimi, i did the formula and got 4+or2root6, is that right?
 2 years ago

simarilli Group TitleBest ResponseYou've already chosen the best response.1
Ravi, in case you were wondering why it's wrong it's because you must factorise the equation equal to 0. 8 has an infinite number of noninteger factors, so you can't solve. 0, on the other hand, must have the value of a factor as 0.
 2 years ago

beth12345 Group TitleBest ResponseYou've already chosen the best response.0
thanks samarilli, i see now why it's not the same answer as when i use the formula
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Well, i got \[\frac{8\pm\sqrt{96}}{2} \]
 2 years ago

ravi623 Group TitleBest ResponseYou've already chosen the best response.0
thanks Simarilli
 2 years ago
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