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beth12345
 4 years ago
how to find the value of 'X' when x^28x=8?
beth12345
 4 years ago
how to find the value of 'X' when x^28x=8?

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Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.3\[x^28x8 = 0 \] Use the quadratic formula: \[\frac{(b)\pm\sqrt{(b)^{2}4(a)(c)}}{2(a)} \] \[a = 1 , b=8 , c = 8\] And sub it in.

Mohammad_Asad_Ali
 4 years ago
Best ResponseYou've already chosen the best response.0use the quadratic formula. \[(b \pm \sqrt{b ^{2} 4ac}) /2a \]

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0x^28x=8 x(x8)=8 or x=2 and x8=4 x=2, x=12

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0thank you, i never thouht of it that way but i can see how it works :)

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0but this solution is wrong

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0x=2, x=12 is a wrong solution

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.3Completing the square would work as well. But using the quadratic formula is easier.

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0i thought it would be like (2)[(12)8]=8?

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok, mimi, i did the formula and got 4+or2root6, is that right?

simarilli
 4 years ago
Best ResponseYou've already chosen the best response.1Ravi, in case you were wondering why it's wrong it's because you must factorise the equation equal to 0. 8 has an infinite number of noninteger factors, so you can't solve. 0, on the other hand, must have the value of a factor as 0.

beth12345
 4 years ago
Best ResponseYou've already chosen the best response.0thanks samarilli, i see now why it's not the same answer as when i use the formula

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.3Well, i got \[\frac{8\pm\sqrt{96}}{2} \]
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