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JamesJBest ResponseYou've already chosen the best response.0
first simplify the RHS (right hand side), what do you get?
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
well it will equal 5=4+(4x+5) and you would solve from there, but OH WAIT. haha for some reason when i was trying to solve it i wrote 4 times (4x+5)
 2 years ago

JamesJBest ResponseYou've already chosen the best response.0
@crazzy: it's actually almost never helpful just to give an answer without explaining how you got the answer. But now that you've given the answer, you can now explain step by step how you got there. :)
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
could you help me with another problem? \[9^{x5} = 81^{3}\]
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
waiiit.. james j :/ hahah
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[\log(ab)=\log(a)+\log(b)\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[\log(5)=\log(4(4x+5))\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
so now we can set the insides equal
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
THAT'S WHY I HAD IT MULTIPLYING. haha sweet (:
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[5=16x+20\] I distributed the 4 here
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
Now I'm going to subtract 20 on both sides \[520=16x\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[15=16x => 16x=15 \]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
Now we divide both sides by 16 \[x=\frac{15}{16}\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
But a negative divided by a negative is positive
 2 years ago

sasogeekBest ResponseYou've already chosen the best response.0
what did i do wrong? my answer doesn't concur with yours myininaya... :
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
i think that's right though because when i tried to solve it on my own i got one, and 15/16 .9375
 2 years ago

sasogeekBest ResponseYou've already chosen the best response.0
i know my working is wrong, i don't see where i went wrong though...
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
myininaya could you help me with the other equation i put up there please?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
@saso I can't read yours that well
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
sasogeek, you didn't just cancle out the log, you cancled the five as well, right?
 2 years ago

Mr.crazzyBest ResponseYou've already chosen the best response.0
thanks for ur advice james
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
Taranicolee you can post if you wish
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
sasogeek you have to distribute the four before you subtract from in the parenthesis
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
oh wait that's not it
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
by the way \[\log(4x+5) \neq \log(4x)+\log(5) \]
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
\[9^{x 5}=81^{3}\]
 2 years ago

sasogeekBest ResponseYou've already chosen the best response.0
i'm just noticing that, thanks for pointing it out. i forgot the log(ab)=log(a)+log(b) rule :)
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
so i just replaced 81 with 9 squared
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
ohh to get the bases the same so you can cancle out right?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
now law of exponents tells us \[(x^a)^b=x^{a \cdot b}\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
if you get the same base on both sides then the exponents have to be equal in order for the equation to hold
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[9^{x5}=9^6 =>x5=6\]
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
you multiplied the exponents on the right side of the equation right ? then cancled out the bases and now to solve you just add five to 6?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
do you recall the law of exponent i mentioned?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[(x^a)^b=x^{a \cdot b} \]?
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
nope. i wasn't here for the teaching of this
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
yes if is it in the form you just multiply the exponents to simplify
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
so for example if we have \[(3^2)^3=3^{2 \cdot 3} =3^6 \]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
or if we have \[(43^4)^3=43^{4 \cdot 3} =43^{12}\]
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
oh sweet ! you're awesome. wanna move to italy and be my tutor?? hahah. if the equation were \[16^{x}=8\] not in that form, how would you solve?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
I would love to go to Italy. write both sides with same base both 16 and 8 can be written as 2 to the power of something
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
\[(2^4)^x=2^3\] so this is our equation
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
cancle bases, 4x=3 divide by 4 on both sides?
 2 years ago

taranicoleeBest ResponseYou've already chosen the best response.1
YAYYYY. thank you !!!!
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
Thank you for being eager to learn this stuff.
 2 years ago
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