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anonymous
 5 years ago
square root problem
anonymous
 5 years ago
square root problem

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the expression \[\sqrt[4]{16x ^{2}y ^{7}?}\] is equivalent to which? 2x^(1/2)y^(7/4) , 4x^(1/2)y^(7/4), 2x^8y^28, or 4x^8y^28.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it took me so long

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the the fundamental rule with radicals that (ab)^(1/2) = (a)^(1/2) * (b)^(1/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you understand radicals? They are simply used to determine what two (or 4 in this case) identical numbers multiply together to give what is under the radical for example 3^(2) = 9 3*3 = 9 (9)^(1/2) =3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know but how does that help me find what the equation is equivalent to?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so split up the terms of your problem into (16)^(1/4) * (x^(2))^(1/4) * (y^(7))^(1/4) I will solve the first term to show you how to solve this so we have (16)^(1/4) if you raise 2^(4) you realize you can get 16 so it simplifies to just 2 so now you are left with 2 * (x^(2))^(1/4) * (y^(7))^(1/4) Now to solve a variable what times what give y^(7) that will allow it to be simplified (when multiplying numbers with exponents we add the exponents). so we have 2 * (x^(2))^(1/4) * (y^(4))^(1/4) * (y^(3))^(1/4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know what the next step is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0remember the rule that (x^(4))^(1/4) is the same as x^((x/1)(1/4)) = x^(1) = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0um do i i change (x^2)^1/4 into x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait apply the rule I just showed you so (x^(2))^(1/4) = x^((2/1)(1/4))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know how to multiply fractions right and that all numbers can be expressed with a 1 in the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and how to simplify fractions right? (2/4) = (1/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya so um it turns out to be x^1/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is (y^(3))^(1/4) simplified?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y^(7/4) can be simplified more you would know that if you read what I posted

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can split up numbers and variables to aid in simplification of them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya but that is what it looks like as one of the answer choices

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok weird sorry for the accusation hope I was helpful
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