Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

cathyangs Group TitleBest ResponseYou've already chosen the best response.0
which is?
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
the expression \[\sqrt[4]{16x ^{2}y ^{7}?}\] is equivalent to which? 2x^(1/2)y^(7/4) , 4x^(1/2)y^(7/4), 2x^8y^28, or 4x^8y^28.
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
sorry it took me so long
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
Use the the fundamental rule with radicals that (ab)^(1/2) = (a)^(1/2) * (b)^(1/2)
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
Do you understand radicals? They are simply used to determine what two (or 4 in this case) identical numbers multiply together to give what is under the radical for example 3^(2) = 9 3*3 = 9 (9)^(1/2) =3
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
i know but how does that help me find what the equation is equivalent to?
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
so split up the terms of your problem into (16)^(1/4) * (x^(2))^(1/4) * (y^(7))^(1/4) I will solve the first term to show you how to solve this so we have (16)^(1/4) if you raise 2^(4) you realize you can get 16 so it simplifies to just 2 so now you are left with 2 * (x^(2))^(1/4) * (y^(7))^(1/4) Now to solve a variable what times what give y^(7) that will allow it to be simplified (when multiplying numbers with exponents we add the exponents). so we have 2 * (x^(2))^(1/4) * (y^(4))^(1/4) * (y^(3))^(1/4)
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
do you know what the next step is?
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
remember the rule that (x^(4))^(1/4) is the same as x^((x/1)(1/4)) = x^(1) = x
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
um do i i change (x^2)^1/4 into x?
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
wait apply the rule I just showed you so (x^(2))^(1/4) = x^((2/1)(1/4))
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
you know how to multiply fractions right and that all numbers can be expressed with a 1 in the denominator
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
and how to simplify fractions right? (2/4) = (1/2)
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
ya so um it turns out to be x^1/2?
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
what is (y^(3))^(1/4) simplified?
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
2x^1/2 and y^7/4
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
y^(7/4) can be simplified more you would know that if you read what I posted
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
you can split up numbers and variables to aid in simplification of them
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
ya but that is what it looks like as one of the answer choices
 2 years ago

BlingBlong Group TitleBest ResponseYou've already chosen the best response.1
oh ok weird sorry for the accusation hope I was helpful
 2 years ago

invisadude Group TitleBest ResponseYou've already chosen the best response.0
ya u were ty
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.