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chungerforever

  • 4 years ago

double check my answer? The product of (a − b)(a − b) is a^2 − b^2. The choices are always, sometimes, and never. I chose always is that correct?

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  1. chungerforever
    • 4 years ago
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    thanks(:

  2. Callum29
    • 4 years ago
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    erm...The product \[(a − b)(a − b) = a^2 -2ab + b^2\]

  3. chungerforever
    • 4 years ago
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    so the answer is not always?

  4. Callum29
    • 4 years ago
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    correct, it would only be that \[(a−b)(a−b)=a^2+b^2\] if either a or b is zero. In that case, you would get either \[a^2\] or \[b^2\] only. So sometimes true i.e. only when a=0 or b=0 or both (trivial). If a and b are each not zero, then it is not true.

  5. anonymous
    • 4 years ago
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    i guess it could be true of b was zero

  6. anonymous
    • 4 years ago
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    it would not be true if \[a=0\]

  7. Mr.crazzy
    • 4 years ago
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    @satellite73 it true for both man , when it is a=0 0r b=0

  8. mathmate
    • 4 years ago
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    Sometimes, (a-b)^2=a^2-b^2 iff b=0 if a=0, b not equal to zero, then (a-b)^2=+b^2 a^2-b^2=-b^2

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