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chungerforever
 3 years ago
double check my answer? The product of (a − b)(a − b) is a^2 − b^2.
The choices are always, sometimes, and never. I chose always is that correct?
chungerforever
 3 years ago
double check my answer? The product of (a − b)(a − b) is a^2 − b^2. The choices are always, sometimes, and never. I chose always is that correct?

This Question is Closed

Callum29
 3 years ago
Best ResponseYou've already chosen the best response.3erm...The product \[(a − b)(a − b) = a^2 2ab + b^2\]

chungerforever
 3 years ago
Best ResponseYou've already chosen the best response.0so the answer is not always?

Callum29
 3 years ago
Best ResponseYou've already chosen the best response.3correct, it would only be that \[(a−b)(a−b)=a^2+b^2\] if either a or b is zero. In that case, you would get either \[a^2\] or \[b^2\] only. So sometimes true i.e. only when a=0 or b=0 or both (trivial). If a and b are each not zero, then it is not true.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1i guess it could be true of b was zero

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1it would not be true if \[a=0\]

Mr.crazzy
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 it true for both man , when it is a=0 0r b=0

mathmate
 3 years ago
Best ResponseYou've already chosen the best response.0Sometimes, (ab)^2=a^2b^2 iff b=0 if a=0, b not equal to zero, then (ab)^2=+b^2 a^2b^2=b^2
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