Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
chungerforever
Group Title
double check my answer? The product of (a − b)(a − b) is a^2 − b^2.
The choices are always, sometimes, and never. I chose always is that correct?
 2 years ago
 2 years ago
chungerforever Group Title
double check my answer? The product of (a − b)(a − b) is a^2 − b^2. The choices are always, sometimes, and never. I chose always is that correct?
 2 years ago
 2 years ago

This Question is Closed

chungerforever Group TitleBest ResponseYou've already chosen the best response.0
thanks(:
 2 years ago

Callum29 Group TitleBest ResponseYou've already chosen the best response.3
erm...The product \[(a − b)(a − b) = a^2 2ab + b^2\]
 2 years ago

chungerforever Group TitleBest ResponseYou've already chosen the best response.0
so the answer is not always?
 2 years ago

Callum29 Group TitleBest ResponseYou've already chosen the best response.3
correct, it would only be that \[(a−b)(a−b)=a^2+b^2\] if either a or b is zero. In that case, you would get either \[a^2\] or \[b^2\] only. So sometimes true i.e. only when a=0 or b=0 or both (trivial). If a and b are each not zero, then it is not true.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i guess it could be true of b was zero
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
it would not be true if \[a=0\]
 2 years ago

Mr.crazzy Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 it true for both man , when it is a=0 0r b=0
 2 years ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
Sometimes, (ab)^2=a^2b^2 iff b=0 if a=0, b not equal to zero, then (ab)^2=+b^2 a^2b^2=b^2
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.