double check my answer? The product of (a − b)(a − b) is a^2 − b^2. The choices are always, sometimes, and never. I chose always is that correct?

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double check my answer? The product of (a − b)(a − b) is a^2 − b^2. The choices are always, sometimes, and never. I chose always is that correct?

Mathematics
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thanks(:
erm...The product \[(a − b)(a − b) = a^2 -2ab + b^2\]
so the answer is not always?

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correct, it would only be that \[(a−b)(a−b)=a^2+b^2\] if either a or b is zero. In that case, you would get either \[a^2\] or \[b^2\] only. So sometimes true i.e. only when a=0 or b=0 or both (trivial). If a and b are each not zero, then it is not true.
i guess it could be true of b was zero
it would not be true if \[a=0\]
@satellite73 it true for both man , when it is a=0 0r b=0
Sometimes, (a-b)^2=a^2-b^2 iff b=0 if a=0, b not equal to zero, then (a-b)^2=+b^2 a^2-b^2=-b^2

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