anonymous
  • anonymous
What is the largest value of "x" (in radians) less than pi satisfying the equation: cos x = cos (6x)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
0
anonymous
  • anonymous
is it the largest though?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=graph+cos%28x%29%2C+cos%286x%29+from+0+to+pi

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anonymous
  • anonymous
it's the largest value of x, not the largest value of solution
TuringTest
  • TuringTest
right, I misunderstood
myininaya
  • myininaya
i'm getting x=4pi/5
myininaya
  • myininaya
\[\cos(x+2 \pi n)=\cos(6x) => x+2\pi n=6x\]
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=graph+cos%28x%29%2C+cos%286x%29+from+2.69+to+2.695
myininaya
  • myininaya
\[5x=2\pi n => x=\frac{2 \pi n}{5}\]
myininaya
  • myininaya
so if n=4 x
myininaya
  • myininaya
oops n=2
anonymous
  • anonymous
Myininaya is right
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
What's the Python solution to this problem? import sympy. sympy.solve(cos(x) = cos(6x))

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