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moneybird

  • 2 years ago

What is the largest value of "x" (in radians) less than pi satisfying the equation: cos x = cos (6x)

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  1. agdgdgdgwngo
    • 2 years ago
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    0

  2. moneybird
    • 2 years ago
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    is it the largest though?

  3. agdgdgdgwngo
    • 2 years ago
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    http://www.wolframalpha.com/input/?i=graph+cos%28x%29%2C+cos%286x%29+from+0+to+pi

  4. moneybird
    • 2 years ago
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    it's the largest value of x, not the largest value of solution

  5. TuringTest
    • 2 years ago
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    right, I misunderstood

  6. myininaya
    • 2 years ago
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    i'm getting x=4pi/5

  7. myininaya
    • 2 years ago
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    \[\cos(x+2 \pi n)=\cos(6x) => x+2\pi n=6x\]

  8. agdgdgdgwngo
    • 2 years ago
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    http://www.wolframalpha.com/input/?i=graph+cos%28x%29%2C+cos%286x%29+from+2.69+to+2.695

  9. myininaya
    • 2 years ago
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    \[5x=2\pi n => x=\frac{2 \pi n}{5}\]

  10. myininaya
    • 2 years ago
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    so if n=4 x<pi

  11. myininaya
    • 2 years ago
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    oops n=2

  12. agdgdgdgwngo
    • 2 years ago
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    Myininaya is right

  13. moneybird
    • 2 years ago
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    ok thank you

  14. agdgdgdgwngo
    • 2 years ago
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    What's the Python solution to this problem? import sympy. sympy.solve(cos(x) = cos(6x))

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