moneybird
What is the largest value of "x" (in radians) less than pi satisfying the equation: cos x = cos (6x)



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agdgdgdgwngo
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moneybird
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is it the largest though?


moneybird
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it's the largest value of x, not the largest value of solution

TuringTest
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right, I misunderstood

myininaya
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i'm getting x=4pi/5

myininaya
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\[\cos(x+2 \pi n)=\cos(6x) => x+2\pi n=6x\]


myininaya
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\[5x=2\pi n => x=\frac{2 \pi n}{5}\]

myininaya
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so if n=4
x<pi

myininaya
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oops n=2

agdgdgdgwngo
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Myininaya is right

moneybird
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ok thank you

agdgdgdgwngo
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What's the Python solution to this problem?
import sympy.
sympy.solve(cos(x) = cos(6x))