anonymous
  • anonymous
Anybody here good at physics and curious to know how long it takes a speeding Moped to reach Ke$ha?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The moped accelerates uniformly over a time of 5.21 seconds for a distance of 110 meters. I have to a) find the average velocity, b) find the velocity at 5.21 seconds, and c) determine acceleration of the Moped.
anonymous
  • anonymous
I'm pretty sure that the average velocity is 21.11 m/s (distance/time), but I'm unsure how to solve the others. Help?
anonymous
  • anonymous
does the moped start from rest?

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anonymous
  • anonymous
I'm assuming so
anonymous
  • anonymous
My formula chart sez \[\Delta d = v_i \Delta t + \frac{1}{2}a (\Delta t)^2\] and you know d, v_initial, and t, so it's easy to solve for "a" ...
anonymous
  • anonymous
average velocity= (u+v)\2=21.21 m\s v=u+at u+v=42.22 m\s
anonymous
  • anonymous
final velocity is pretty fast, can we hope that Ke$ha won't be able to get out of the way of the speeding moped?
anonymous
  • anonymous
42.22-u=u+at 2u=42.22-5.21 a
anonymous
  • anonymous
lol @ fixer... but your formula is way too intense for me :) I think that there's a way to figure it out without one other than the basics...
anonymous
  • anonymous
ravi: what do u and v stand for?
anonymous
  • anonymous
i think ravi is saying that final velocity is twice average velocity (since initial velocity is zero), and than acceleration is (final velocity) / (time).
anonymous
  • anonymous
a=(42.22-2u)\2 u=initial velocity v=final velocity a=acceleration
anonymous
  • anonymous
hold on... let me process that information...
anonymous
  • anonymous
ravi- how'd you get 21.21? My calculations give 21.11
anonymous
  • anonymous
sir, it was written by mistake
anonymous
  • anonymous
okay, so it is 21.11? and then from there you said that velocity=initial velocity + acceleration * time?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
and after that was initial velocity + final velocity= 42.22 m/s. Where did 42.22 come from?
anonymous
  • anonymous
everyone whos good at physics are at physics group
anonymous
  • anonymous
no one in the physics group :P
anonymous
  • anonymous
distance traveled=(average velocity). time=110
anonymous
  • anonymous
im glad some one could help u
anonymous
  • anonymous
20ppl there
anonymous
  • anonymous
Ravi? Where's u go :(
anonymous
  • anonymous
i am here
anonymous
  • anonymous
u+v=42.22 v-u=5.21 a so adding these equation, we get 2v=42.22+5.21a
anonymous
  • anonymous
v=(42.22+5.11a)\2
anonymous
  • anonymous
a=(v-u)\t if moped started from rest then a=v\t=v\5.11
anonymous
  • anonymous
now we have final equation for v v=( 42.22+5.11*(v\5.11) ) \ 2 solving this equation for v, we can find the value of final velocity .
anonymous
  • anonymous
here average velocity= (u+v)\2

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