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gandalfwiz
 4 years ago
Anybody here good at physics and curious to know how long it takes a speeding Moped to reach Ke$ha?
gandalfwiz
 4 years ago
Anybody here good at physics and curious to know how long it takes a speeding Moped to reach Ke$ha?

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gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1The moped accelerates uniformly over a time of 5.21 seconds for a distance of 110 meters. I have to a) find the average velocity, b) find the velocity at 5.21 seconds, and c) determine acceleration of the Moped.

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1I'm pretty sure that the average velocity is 21.11 m/s (distance/time), but I'm unsure how to solve the others. Help?

Broken_Fixer
 4 years ago
Best ResponseYou've already chosen the best response.1does the moped start from rest?

Broken_Fixer
 4 years ago
Best ResponseYou've already chosen the best response.1My formula chart sez \[\Delta d = v_i \Delta t + \frac{1}{2}a (\Delta t)^2\] and you know d, v_initial, and t, so it's easy to solve for "a" ...

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0average velocity= (u+v)\2=21.21 m\s v=u+at u+v=42.22 m\s

Broken_Fixer
 4 years ago
Best ResponseYou've already chosen the best response.1final velocity is pretty fast, can we hope that Ke$ha won't be able to get out of the way of the speeding moped?

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.042.22u=u+at 2u=42.225.21 a

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1lol @ fixer... but your formula is way too intense for me :) I think that there's a way to figure it out without one other than the basics...

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1ravi: what do u and v stand for?

Broken_Fixer
 4 years ago
Best ResponseYou've already chosen the best response.1i think ravi is saying that final velocity is twice average velocity (since initial velocity is zero), and than acceleration is (final velocity) / (time).

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0a=(42.222u)\2 u=initial velocity v=final velocity a=acceleration

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1hold on... let me process that information...

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1ravi how'd you get 21.21? My calculations give 21.11

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0sir, it was written by mistake

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1okay, so it is 21.11? and then from there you said that velocity=initial velocity + acceleration * time?

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1and after that was initial velocity + final velocity= 42.22 m/s. Where did 42.22 come from?

Tomas.A
 4 years ago
Best ResponseYou've already chosen the best response.0everyone whos good at physics are at physics group

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1no one in the physics group :P

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0distance traveled=(average velocity). time=110

sunsetlove
 4 years ago
Best ResponseYou've already chosen the best response.2im glad some one could help u

gandalfwiz
 4 years ago
Best ResponseYou've already chosen the best response.1Ravi? Where's u go :(

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0u+v=42.22 vu=5.21 a so adding these equation, we get 2v=42.22+5.21a

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0a=(vu)\t if moped started from rest then a=v\t=v\5.11

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0now we have final equation for v v=( 42.22+5.11*(v\5.11) ) \ 2 solving this equation for v, we can find the value of final velocity .

ravi623
 4 years ago
Best ResponseYou've already chosen the best response.0here average velocity= (u+v)\2
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