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does the moped start from rest?

I'm assuming so

average velocity= (u+v)\2=21.21 m\s
v=u+at
u+v=42.22 m\s

42.22-u=u+at
2u=42.22-5.21 a

ravi: what do u and v stand for?

a=(42.22-2u)\2
u=initial velocity
v=final velocity
a=acceleration

hold on... let me process that information...

ravi- how'd you get 21.21? My calculations give 21.11

sir, it was written by mistake

yeah

and after that was initial velocity + final velocity= 42.22 m/s. Where did 42.22 come from?

everyone whos good at physics are at physics group

no one in the physics group :P

distance traveled=(average velocity). time=110

im glad some one could help u

20ppl there

Ravi? Where's u go :(

i am here

u+v=42.22
v-u=5.21 a
so adding these equation, we get
2v=42.22+5.21a

v=(42.22+5.11a)\2

a=(v-u)\t
if moped started from rest then
a=v\t=v\5.11

here average velocity= (u+v)\2