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v=u+at, for first case equation becomes v=-4.2+2.6*t

t=3.7 approx, at t=3.7 seconds, both the toy car will have the same speed

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hello ravi
here initial velocity can be negative? I don't think so.

at the t = 3.7 seconds the speed of first toy car will be v=u+at= -4.2+(2.6)*(3.7) cm\sec

if it is negative then it is decelerating and 1st car will move back other than the second.

speed of second toy car will be the same as that of firsr

initial velocity is negative in the first case but acceleration is positive

I object

how? plz tell

but i mean simply is that the negative sign of velocity does not says that velocity is decreasing

a=v\t is true only if u=o, but here u is not zero
here a=v-u\t

oh yes
now that's a point. I got you ravi623. That was helpful.

So, what are the times when they pass each other?

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