Here's the question you clicked on:
tena32
factor... x^11(x+12)+10(x+12)
x^(12) + 12x^(11) +10x+120 = (x^(11) + 10)(x + 12)
what times what gives 120 the think when I add x values what will I get
am i using 12 because its common in both factors?
you are using 12 because 12 * 10 = 120
also think about it 12*x^(11) = 12x^(11) and 10 * x = 10x
i think that is the way i worked it, but i still came up with the same answer as you did. thanks for the help.
meh factoring isn't hard you just need to develop the thought process
yea. what i did was took the common factors and used them. I think my problem is trying to find the "short" ways to figure out problems. most of the time i get them correct lol