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Find the quadratic equation whose solutions are:
2 + sqr(5) and 2  sqr(5)
I'm not just looking for an answer but rather to learn.
 2 years ago
 2 years ago
Find the quadratic equation whose solutions are: 2 + sqr(5) and 2  sqr(5) I'm not just looking for an answer but rather to learn.
 2 years ago
 2 years ago

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TrumanBest ResponseYou've already chosen the best response.0
\[2+ \sqrt{5} and 2  \sqrt{5}\]
 2 years ago

amitlpu91Best ResponseYou've already chosen the best response.1
equation bcam x^2  (a+b)x+ a.b =0 take a=2+sqr 5 , b=2sqr 5
 2 years ago

TrumanBest ResponseYou've already chosen the best response.0
\[x ^{2}  (a+b)x + ab = 0?\]
 2 years ago

TrumanBest ResponseYou've already chosen the best response.0
this is from an example in my book, but I don't understand the example:
 2 years ago

amitlpu91Best ResponseYou've already chosen the best response.1
tis what any quarratic equation can be form...
 2 years ago

amitlpu91Best ResponseYou've already chosen the best response.1
if their two roots are given .got it ...now
 2 years ago

TrumanBest ResponseYou've already chosen the best response.0
that's the example from the book
 2 years ago

amitlpu91Best ResponseYou've already chosen the best response.1
yea ........now plug in...
 2 years ago

imperialistBest ResponseYou've already chosen the best response.0
If you are given 2 (or more than 2, it doesn't matter) roots of a polynomial, say a and b in this case, then that just means if you were to factor your polynomial, you would get \[f(x)=(xa)(xb)\] By multiplying this together, you get the equation \[x^2(a+b)+ab\] Thus, in your example, you would just plug in \[a=2+\sqrt{5}, b=2\sqrt{5}\] to the above equation to reach your answer.
 2 years ago

TrumanBest ResponseYou've already chosen the best response.0
that's the books example typed out,
 2 years ago

TrumanBest ResponseYou've already chosen the best response.0
thank you, i'm trying it
 2 years ago
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