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waheguru
Group Title
by connecting the midpoints of a reatangle u get a rhombus right?
 2 years ago
 2 years ago
waheguru Group Title
by connecting the midpoints of a reatangle u get a rhombus right?
 2 years ago
 2 years ago

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Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
In general you get a parallelogram, which does not necessarily have to be a rhombus.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
No you will get a rhombus always.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
and square gives square.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
Oh my, I was thinking of something else, I apologize. Yep :)
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
A square is a rhombus though.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
No problem :)
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
If you join the midpoints of a square the secondary figure is also a square.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
Yes, but I meant that a square is also a rhombus.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
Every square is rhombus, rectangle and parallelogram.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
I disagree. A rhombus is a quadrilateral with all four sides being of the same length. A square is an example of this.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
I don't mean that to be a square is to be a rhombus, I mean that a square happens to be a particular example of a rhombus.
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
Yes it's always precise to use the subset instead of superset when your conditions satisfies the subset. Say what is 2 ? It is an integer and also real but we generally say integer.
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
Why not natural then?
 2 years ago

FoolForMath Group TitleBest ResponseYou've already chosen the best response.1
Yes, but it depends on the problem again we can call it whole too.
 2 years ago

waheguru Group TitleBest ResponseYou've already chosen the best response.2
Do i get a metal for asking a good question =)
 2 years ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
We could also call it prime, which is even more precise. I disagree that it's always better to specify the subset rather than the superset. In that case, the best classification of 2 would be "the number 2". Regardless. The question was answered, the points were made. End of thread. And sure^, why not.
 2 years ago

waheguru Group TitleBest ResponseYou've already chosen the best response.2
yaay im level 18
 2 years ago
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