The diagonal of a particular square is 5 inches. The diameter of
a particular circle is also 5 inches. By how many square inches
is the area of the circle greater than the area of square? Express
your answer as a decimal to the nearest tenth.

area of circle is pir^2 = pi*2.5^2
side of square by pythagoras
5^2 = 2x^2
x^2 = 12.5 = area of the square
area of circle = pi * 6.25 = 19.63
difference in areas = 19.63 - 12.5 = 7.13 sq ins