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The diagonal of a particular square is 5 inches. The diameter of a particular circle is also 5 inches. By how many square inches is the area of the circle greater than the area of square? Express your answer as a decimal to the nearest tenth.

Mathematics
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Other answers:

area of circle is pir^2 = pi*2.5^2 side of square by pythagoras 5^2 = 2x^2 x^2 = 12.5 = area of the square area of circle = pi * 6.25 = 19.63 difference in areas = 19.63 - 12.5 = 7.13 sq ins
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