Here's the question you clicked on:
candycane2565
Solve. 2x2 + x = 15.
I'm assuming that means \[2x ^{2} + x = 15\]?
2x2 + x = 15 2x2 + x -15 =0 (2x-5)(x+3)=0 x= 5/2 OR x=-3
okay, you'll need to use the quadratic formula: \[ \frac{-b \pm \sqrt{b ^{2}} - 4ac}{2a}\]
\[2x^2+x-15=0\] \[(2x-5)(x+3)=0\] x=2,5 or -3
@sfozturk61 2&5 are not solutions 5/2 & -3 are the only solutions **
Rewrite as 2x^2 +6x - 5x -15. Now factor by grouping 2x(x +3) - 5(x + 3). Factors to (2x- 5)(x+3)= 0 x=5/2 and -3
@hoblos I mean 2,5 so 2 and one half = 5/2