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candycane2565

  • 4 years ago

Solve. 2x2 + x = 15.

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  1. MSMR
    • 4 years ago
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    I'm assuming that means \[2x ^{2} + x = 15\]?

  2. candycane2565
    • 4 years ago
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    yes

  3. hoblos
    • 4 years ago
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    2x2 + x = 15 2x2 + x -15 =0 (2x-5)(x+3)=0 x= 5/2 OR x=-3

  4. MSMR
    • 4 years ago
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    okay, you'll need to use the quadratic formula: \[ \frac{-b \pm \sqrt{b ^{2}} - 4ac}{2a}\]

  5. sfozturk61
    • 4 years ago
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    \[2x^2+x-15=0\] \[(2x-5)(x+3)=0\] x=2,5 or -3

  6. hoblos
    • 4 years ago
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    @sfozturk61 2&5 are not solutions 5/2 & -3 are the only solutions **

  7. nickup
    • 4 years ago
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    Rewrite as 2x^2 +6x - 5x -15. Now factor by grouping 2x(x +3) - 5(x + 3). Factors to (2x- 5)(x+3)= 0 x=5/2 and -3

  8. sfozturk61
    • 4 years ago
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    @hoblos I mean 2,5 so 2 and one half = 5/2

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