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anonymous
 5 years ago
Find the exact area between y=ln(x) and y= ln(x^2) when 1=/<x </=2
anonymous
 5 years ago
Find the exact area between y=ln(x) and y= ln(x^2) when 1=/<x </=2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How would you set up this equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi handy dandy helpers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326752403115:dw

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits_{1}^{2}(\ln(x^2)\ln(x)) dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you explain why mininaya?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2because of your graph lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol you're right any questions rl?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks myin and no data

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2it always helps to draw a picture first or to graph using your calculator

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2then do \[\int\limits_{lowerlimit}^{upperlimit} (upperfunction lowerfunction) dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is great mininaya.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the upper function wld be the one with x^2 obviously?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But what if he don't have a graphing calculator at hand?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2he will have to draw it with out one then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No data i am not sam now LOL

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am a she at the prsesnt moment

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2also you may come of course some these when the functions with change from upper to lower and then you will have to break the integral up

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2for example dw:1326753034373:dw

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2if i wanted the area btw a and b bounded by g and f

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits_{a}^{c}(fg) dx+\int\limits_{c}^{b}(gf) dx\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2then i would set up like that since f is the upper from a to c and g is the upper from c to b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok i c so basically u will have to draw the function and then decide which goes first

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2yep drawing or seeing the graph is totally important

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok thanks for the tip myin u r awesome :DDDD
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