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anonymous

  • 5 years ago

. A 25 ft ladder is leaning against a vertical wall. The bottom of the ladder is pulled horizontally away from the wall at 3 ft/sec. Determine how fast the top of the ladder is sliding when the bottom of the ladder is 15 ft from the wall. A) –4 ft/sec B) –2.25 ft/sec C) –13.375 ft/sec D)–12.25 ft/sec E) –0.75 ft/sec

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  1. anonymous
    • 5 years ago
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    first write the position of the top as a function of the position of the bottom

  2. anonymous
    • 5 years ago
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    How do I do that? please explain in detail

  3. anonymous
    • 5 years ago
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    although if you don't have to show your work, you can just guess the sensible answer

  4. anonymous
    • 5 years ago
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    Put the bottom of the ladder at (x,0) and the top of the ladder at (0,y). How would you write the constraint requirement that the ladder is length 25?

  5. anonymous
    • 5 years ago
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    Hint.|dw:1326760267836:dw|

  6. anonymous
    • 5 years ago
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    pathagoren Theorem?

  7. anonymous
    • 5 years ago
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    Yes, sounds true to me

  8. anonymous
    • 5 years ago
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    So then I take the derivative of the Theorem?

  9. anonymous
    • 5 years ago
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    Yes, if you're in the Implicit Differentiation section. If you want to do it a longer easier way, just write y as a function of x, then replace x by (3t) because x(t) = 3t and differentiate your y(t) with respect to t at time t=5 because x=15.

  10. anonymous
    • 5 years ago
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    so should my derivative read \[dy/dx=(-2x+2c)/(2y)\] ?

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