anonymous
  • anonymous
. A 25 ft ladder is leaning against a vertical wall. The bottom of the ladder is pulled horizontally away from the wall at 3 ft/sec. Determine how fast the top of the ladder is sliding when the bottom of the ladder is 15 ft from the wall. A) –4 ft/sec B) –2.25 ft/sec C) –13.375 ft/sec D)–12.25 ft/sec E) –0.75 ft/sec
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
first write the position of the top as a function of the position of the bottom
anonymous
  • anonymous
How do I do that? please explain in detail
anonymous
  • anonymous
although if you don't have to show your work, you can just guess the sensible answer

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Put the bottom of the ladder at (x,0) and the top of the ladder at (0,y). How would you write the constraint requirement that the ladder is length 25?
anonymous
  • anonymous
Hint.|dw:1326760267836:dw|
anonymous
  • anonymous
pathagoren Theorem?
anonymous
  • anonymous
Yes, sounds true to me
anonymous
  • anonymous
So then I take the derivative of the Theorem?
anonymous
  • anonymous
Yes, if you're in the Implicit Differentiation section. If you want to do it a longer easier way, just write y as a function of x, then replace x by (3t) because x(t) = 3t and differentiate your y(t) with respect to t at time t=5 because x=15.
anonymous
  • anonymous
so should my derivative read \[dy/dx=(-2x+2c)/(2y)\] ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.