A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
A particle moves along a line. The particles position,s, in centimetres at t seconds is modelled by s(t)=t^39t^2+24t+20,where t is greater than or equal to zero. What is the total distance travelled by the particle in the first 8 seconds??
anonymous
 5 years ago
A particle moves along a line. The particles position,s, in centimetres at t seconds is modelled by s(t)=t^39t^2+24t+20,where t is greater than or equal to zero. What is the total distance travelled by the particle in the first 8 seconds??

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We know that the expression \[s(0) +\int_{0}^{8} v(t) dt\] will give the total distance traveled. We can see from the position function that \[s(0)=20\]. From the graph of the velocity function, we can evaluate the definite integral by breaking it into parts "above" and "below" the xaxis. The graph of velocity crosses the xaxis at x=2 and x=4. Thus, we can find the total distance traveled by evaluating the following expression: \[20+\int_{0}^{2} v(t) dt  \int_{2}^{4} v(t) dt + \int_{4}^{8} v(t) dt\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.