## anonymous 4 years ago A 25 ft ladder is leaning against a vertical wall. The bottom of the ladder is pulled horizontally away from the wall at 3 ft/sec. Determine how fast the top of the ladder is sliding when the bottom of the ladder is 15 ft from the wall <----- PLEASE EXPLAIN STEPS!

1. anonymous

|dw:1326763970660:dw| $y=\sqrt{625-x ^{2}}$ $dy/dt = (1/2)(-2x)/\sqrt{625-x ^{2}}(dx/dt)$ so at dx/dt =3 and x=15 dy/dt= -3/4 ft/s negative sign shows ladder is sliding downwards

2. anonymous

sorry multyply 3 also i forget to multiply 3...its -9/4 ft/s