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  1. anonymous
    • 5 years ago
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    click on the link

  2. anonymous
    • 5 years ago
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    what do you want to know..there are a lot of graph mean value theorem is not applicable in all...just ask a perticular question...

  3. anonymous
    • 5 years ago
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    where it asks me to to draw the secant line and tangent line and from the graph c is approximately what

  4. anonymous
    • 5 years ago
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    okay...if the function is diffreciable in an intervel [a,b]... there must be apoint c on the graph at that point tangent to the curve is parellel to secant joining point a and b... you got me???

  5. anonymous
    • 5 years ago
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    yeah

  6. anonymous
    • 5 years ago
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    so what is the slope of secant ???... its [f(b)-f(a)]/(b-a) and slope of tangent at point c??? f'(c) so f'(c) = [f(b)-f(a)]/(b-a) thats the mean value theorem..

  7. anonymous
    • 5 years ago
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    so on the first problem how and hwere will i draw the secant and tangent if u could grpah it forme here

  8. anonymous
    • 5 years ago
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    |dw:1326765928018:dw|

  9. anonymous
    • 5 years ago
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    f(x)=.1 x^3 +1.2 x^2 -3.6 x +5 so what are f(3) and f(7) ????

  10. anonymous
    • 5 years ago
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    when you find f(7)-f(3) divide them by 7 - 3..here it is slope of tangent.. now find f'(c)..put them equal and find the value c...

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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