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anonymous
 5 years ago
anonymous
 5 years ago

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you want to know..there are a lot of graph mean value theorem is not applicable in all...just ask a perticular question...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where it asks me to to draw the secant line and tangent line and from the graph c is approximately what

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay...if the function is diffreciable in an intervel [a,b]... there must be apoint c on the graph at that point tangent to the curve is parellel to secant joining point a and b... you got me???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what is the slope of secant ???... its [f(b)f(a)]/(ba) and slope of tangent at point c??? f'(c) so f'(c) = [f(b)f(a)]/(ba) thats the mean value theorem..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so on the first problem how and hwere will i draw the secant and tangent if u could grpah it forme here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326765928018:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=.1 x^3 +1.2 x^2 3.6 x +5 so what are f(3) and f(7) ????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you find f(7)f(3) divide them by 7  3..here it is slope of tangent.. now find f'(c)..put them equal and find the value c...
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