Help with the mean value theorem https://docs.google.com/viewer?a=v&q=cache:I5OPJb0Q_ugJ:www.sd84.k12.id.us/shs/departments/Math/Search/Calculus/expl5-5a%2520meanvalth.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESgH1Cz6DLBouaBtF8rObDqCh3aG8o49TeXx5gSOa18XUKm3HTLekNEjI2TwoPFiqnH11MgwjiLruBAGRsh-hBJvF3GHfHRUtdAr39ii_wy2Pi2nAXtda3334Xem8hgzHPacYJrf&sig=AHIEtbT4PsvTDdhjAMtR6M8xmT38ZvSKeQ

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Help with the mean value theorem https://docs.google.com/viewer?a=v&q=cache:I5OPJb0Q_ugJ:www.sd84.k12.id.us/shs/departments/Math/Search/Calculus/expl5-5a%2520meanvalth.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESgH1Cz6DLBouaBtF8rObDqCh3aG8o49TeXx5gSOa18XUKm3HTLekNEjI2TwoPFiqnH11MgwjiLruBAGRsh-hBJvF3GHfHRUtdAr39ii_wy2Pi2nAXtda3334Xem8hgzHPacYJrf&sig=AHIEtbT4PsvTDdhjAMtR6M8xmT38ZvSKeQ

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what do you want to know..there are a lot of graph mean value theorem is not applicable in all...just ask a perticular question...
where it asks me to to draw the secant line and tangent line and from the graph c is approximately what

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okay...if the function is diffreciable in an intervel [a,b]... there must be apoint c on the graph at that point tangent to the curve is parellel to secant joining point a and b... you got me???
yeah
so what is the slope of secant ???... its [f(b)-f(a)]/(b-a) and slope of tangent at point c??? f'(c) so f'(c) = [f(b)-f(a)]/(b-a) thats the mean value theorem..
so on the first problem how and hwere will i draw the secant and tangent if u could grpah it forme here
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f(x)=.1 x^3 +1.2 x^2 -3.6 x +5 so what are f(3) and f(7) ????
when you find f(7)-f(3) divide them by 7 - 3..here it is slope of tangent.. now find f'(c)..put them equal and find the value c...

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