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anonymous
 4 years ago
Indefinite Integral Help
int (x/(2x+1) dx
I keep getting (x/2)((1/4)ln2x+1)+1/4+C
Book says ((1/2)x)((1/4)ln2x+1)+C.
So when I get a constant as part of the answer when trying to find the indefinite integral, do I just consider it as part of the constant C? Is that why I'm off by +1/4?
anonymous
 4 years ago
Indefinite Integral Help int (x/(2x+1) dx I keep getting (x/2)((1/4)ln2x+1)+1/4+C Book says ((1/2)x)((1/4)ln2x+1)+C. So when I get a constant as part of the answer when trying to find the indefinite integral, do I just consider it as part of the constant C? Is that why I'm off by +1/4?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yes, 1/4 is absorbed into C, because C is unknown that will happen a lot in differential equations, so get used to it

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5yes whenever you have another constant, you ought to add it into C. The C absorbs it.. If you are having marks for steps then this step will count for marks as well ( maybe 1/2 mark or so if u r scoring full elsewhere)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1wolfram keeps the 1 though ironically http://www.wolframalpha.com/input/?i=int%20(x%2F(2x%2B1)%20dx&t=crmtb01 but they left it in the parentheses, so I guess they feel it's justified

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5but in the alternate forms it does absorb the constant :D

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5turing i need u 1 min

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5i will give u the link

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5http://openstudy.com/study#/updates/4f14d598e4b0b9109c920bca

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1I don't even see why they add the 1 for 'restricted values of x' in wolf what does that mean, do you know akshay?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0what are you guys doing?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0comparing your answers with wolfram?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0sprusty 1/4+constant is still a constant so your answer and the book answer are fine! :)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yes, but why does wolf add the 1 for 'restricted values' I want to know

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{x}{2x+1} dx\] u=2x+1 => du=2 dx u=2x+1 => (u1)/2=x \[\int\limits_{}^{}x \cdot \frac{1}{2x+1} dx=\int\limits_{}^{}\frac{u1}{2} \cdot \frac{1}{u} \frac{du}{2}\] \[\frac{1}{4}\int\limits_{}^{}\frac{u1}{u} du=\frac{1}{4}\int\limits_{}^{}(1\frac{1}{u}) du=\frac{1}{4}(u\lnu)+C\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[=\frac{1}{4}(2x+1\ln2x+1)+C\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[=\frac{x}{2}+\frac{1}{4}\frac{1}{4} \ln2x+1 +C\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[=\frac{x}{2}\frac{1}{4}\ln2x+1+c \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0i will look at wolfram's solution one sec

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0No I don't know what they are talking about honestly lol

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0either one of those things they have listed is fine though

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0imperialist seems smart I will ask him what he think wolfram means
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