anonymous
  • anonymous
Find The equestion in slope intercept form for the line contaning the two points. (1,1 ) and ( 5,4 )
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1326768472676:dw|
anonymous
  • anonymous
you know how to use the equation?
anonymous
  • anonymous
that gives the gradient of the line

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anonymous
  • anonymous
Do You Start With Y1 Or Y2
anonymous
  • anonymous
call x_1= 1, y_1 =1, x_2=5, y_2 = 4
anonymous
  • anonymous
|dw:1326768658229:dw|
anonymous
  • anonymous
the gradient, m is 3/4
anonymous
  • anonymous
now you want the equation in the form: y=mx + c
anonymous
  • anonymous
y=mx+B
anonymous
  • anonymous
the answer is y = 3/5x -1
anonymous
  • anonymous
i did all my work the answer doesnt show up
anonymous
  • anonymous
do you get emra?
anonymous
  • anonymous
no i didnt get emra she's hard to catch o.O
anonymous
  • anonymous
you know m = 3/4. Take the first coordinate pair (1,1). Set y=1 and x=1. Then: \[1=3/4 + c\] \[c=1/4\] You can check this value by using the other coordinate pair (5,4) \[4=15/4 + c\] \[c=(16-15)/4 = 1/4\] Therefore the equation of your line is \[y=\frac{3}{4}x + \frac{1}{4}\]
anonymous
  • anonymous
it's not y=3/5x - 1 though...
anonymous
  • anonymous
thats how we learned it
anonymous
  • anonymous
oh my bad
anonymous
  • anonymous
i see my mistake
anonymous
  • anonymous
yeah its y = 3/4 x + 1/4
anonymous
  • anonymous
you forgot to minus the 1 from the 5 didn't you?
anonymous
  • anonymous
no i wrote the slope wrong -.-
anonymous
  • anonymous
imm confused alot know
anonymous
  • anonymous
5-1 is 4 right
anonymous
  • anonymous
yeah ^^ i remember when I was doing all that geometry was fun, I went to classes drunk for the lols
anonymous
  • anonymous
lol
anonymous
  • anonymous
5-1 is 4, bravo, bravo
anonymous
  • anonymous
heheheheh
anonymous
  • anonymous
How would you do this one (8,6 ( and (-3,6)
anonymous
  • anonymous
y_2 - y_1 = 6 - 6 = 0 x_2 - x_1 = -3 - 8 = -11
anonymous
  • anonymous
0 -- 11
anonymous
  • anonymous
then what do i do
anonymous
  • anonymous
it's zero yes, what does that mean about the line?
anonymous
  • anonymous
hint: m=0
anonymous
  • anonymous
?/// thats what i dont get ohh m=0 know we have to see what b=
anonymous
  • anonymous
??
anonymous
  • anonymous
go back to the general equation of a line: \[y=mx+b\] in this case, m=0 so it' just \[y=b\] This tells you that the line is a straight line forever, parallel to the x axis and intersecting the y axis at 6. Now look at your two pairs of coordinates. y is 6 in both (it better be)! So the equation of your line is......?
anonymous
  • anonymous
6 ?
anonymous
  • anonymous
6 -- 6 = 0 ??
anonymous
  • anonymous
yes \[y=6\] is the equation of your line, it's a very boring graph if you ask me
anonymous
  • anonymous
so what the equestions y=0x
anonymous
  • anonymous
yes 0x=0 for any x
anonymous
  • anonymous
so it's not in the equation
anonymous
  • anonymous
so whats the equestion then is it y=ox
anonymous
  • anonymous
remember x is a variable, and is allowed to take all values on the real line, but it obeys the law 0x=0
anonymous
  • anonymous
kk is that the equestion
anonymous
  • anonymous
k how would you do this one ( 100,-300 ) and (101,-299 )
anonymous
  • anonymous
do it how you think...
anonymous
  • anonymous
-1 ____ -1 = 1 ?
anonymous
  • anonymous
H-E-L-P
anonymous
  • anonymous
y_2-y_1 = -299 - (-300) = -299 + 300 = 1 x_2 - x_1 = 101 - 100 = 1 so it is 1/1 = 1. Your way worked too which is a good thing!
anonymous
  • anonymous
so yes, you are right
anonymous
  • anonymous
so what would the equestion bee y=-1x+ ??
anonymous
  • anonymous
use y=x+b and one of your coordinate pairs to solve the equation for b. (Gradient is 1 not -1 by the way).

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