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Emra Group Title

Find The equestion in slope intercept form for the line contaning the two points. (1,1 ) and ( 5,4 )

  • 2 years ago
  • 2 years ago

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  1. Mrs.Math101 Group Title
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    |dw:1326768472676:dw|

    • 2 years ago
  2. Mrs.Math101 Group Title
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    you know how to use the equation?

    • 2 years ago
  3. Callum29 Group Title
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    that gives the gradient of the line

    • 2 years ago
  4. Emra Group Title
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    Do You Start With Y1 Or Y2

    • 2 years ago
  5. Callum29 Group Title
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    call x_1= 1, y_1 =1, x_2=5, y_2 = 4

    • 2 years ago
  6. Mrs.Math101 Group Title
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    |dw:1326768658229:dw|

    • 2 years ago
  7. Callum29 Group Title
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    the gradient, m is 3/4

    • 2 years ago
  8. Callum29 Group Title
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    now you want the equation in the form: y=mx + c

    • 2 years ago
  9. Mrs.Math101 Group Title
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    y=mx+B

    • 2 years ago
  10. MohamedDada Group Title
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    the answer is y = 3/5x -1

    • 2 years ago
  11. MohamedDada Group Title
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    i did all my work the answer doesnt show up

    • 2 years ago
  12. Mrs.Math101 Group Title
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    do you get emra?

    • 2 years ago
  13. MohamedDada Group Title
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    no i didnt get emra she's hard to catch o.O

    • 2 years ago
  14. Callum29 Group Title
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    you know m = 3/4. Take the first coordinate pair (1,1). Set y=1 and x=1. Then: \[1=3/4 + c\] \[c=1/4\] You can check this value by using the other coordinate pair (5,4) \[4=15/4 + c\] \[c=(16-15)/4 = 1/4\] Therefore the equation of your line is \[y=\frac{3}{4}x + \frac{1}{4}\]

    • 2 years ago
  15. Callum29 Group Title
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    it's not y=3/5x - 1 though...

    • 2 years ago
  16. MohamedDada Group Title
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    thats how we learned it

    • 2 years ago
  17. MohamedDada Group Title
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    oh my bad

    • 2 years ago
  18. MohamedDada Group Title
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    i see my mistake

    • 2 years ago
  19. MohamedDada Group Title
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    yeah its y = 3/4 x + 1/4

    • 2 years ago
  20. Callum29 Group Title
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    you forgot to minus the 1 from the 5 didn't you?

    • 2 years ago
  21. MohamedDada Group Title
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    no i wrote the slope wrong -.-

    • 2 years ago
  22. Emra Group Title
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    imm confused alot know

    • 2 years ago
  23. Emra Group Title
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    5-1 is 4 right

    • 2 years ago
  24. Callum29 Group Title
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    yeah ^^ i remember when I was doing all that geometry was fun, I went to classes drunk for the lols

    • 2 years ago
  25. MohamedDada Group Title
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    lol

    • 2 years ago
  26. Callum29 Group Title
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    5-1 is 4, bravo, bravo

    • 2 years ago
  27. Emra Group Title
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    heheheheh

    • 2 years ago
  28. Emra Group Title
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    How would you do this one (8,6 ( and (-3,6)

    • 2 years ago
  29. Callum29 Group Title
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    y_2 - y_1 = 6 - 6 = 0 x_2 - x_1 = -3 - 8 = -11

    • 2 years ago
  30. Emra Group Title
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    0 -- 11

    • 2 years ago
  31. Emra Group Title
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    then what do i do

    • 2 years ago
  32. Callum29 Group Title
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    it's zero yes, what does that mean about the line?

    • 2 years ago
  33. Callum29 Group Title
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    hint: m=0

    • 2 years ago
  34. Emra Group Title
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    ?/// thats what i dont get ohh m=0 know we have to see what b=

    • 2 years ago
  35. Emra Group Title
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    ??

    • 2 years ago
  36. Callum29 Group Title
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    go back to the general equation of a line: \[y=mx+b\] in this case, m=0 so it' just \[y=b\] This tells you that the line is a straight line forever, parallel to the x axis and intersecting the y axis at 6. Now look at your two pairs of coordinates. y is 6 in both (it better be)! So the equation of your line is......?

    • 2 years ago
  37. Emra Group Title
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    6 ?

    • 2 years ago
  38. Emra Group Title
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    6 -- 6 = 0 ??

    • 2 years ago
  39. Callum29 Group Title
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    yes \[y=6\] is the equation of your line, it's a very boring graph if you ask me

    • 2 years ago
  40. Emra Group Title
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    so what the equestions y=0x

    • 2 years ago
  41. Callum29 Group Title
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    yes 0x=0 for any x

    • 2 years ago
  42. Callum29 Group Title
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    so it's not in the equation

    • 2 years ago
  43. Emra Group Title
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    so whats the equestion then is it y=ox

    • 2 years ago
  44. Callum29 Group Title
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    remember x is a variable, and is allowed to take all values on the real line, but it obeys the law 0x=0

    • 2 years ago
  45. Emra Group Title
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    kk is that the equestion

    • 2 years ago
  46. Emra Group Title
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    k how would you do this one ( 100,-300 ) and (101,-299 )

    • 2 years ago
  47. Callum29 Group Title
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    do it how you think...

    • 2 years ago
  48. Emra Group Title
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    -1 ____ -1 = 1 ?

    • 2 years ago
  49. Emra Group Title
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    H-E-L-P

    • 2 years ago
  50. Callum29 Group Title
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    y_2-y_1 = -299 - (-300) = -299 + 300 = 1 x_2 - x_1 = 101 - 100 = 1 so it is 1/1 = 1. Your way worked too which is a good thing!

    • 2 years ago
  51. Callum29 Group Title
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    so yes, you are right

    • 2 years ago
  52. Emra Group Title
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    so what would the equestion bee y=-1x+ ??

    • 2 years ago
  53. Callum29 Group Title
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    use y=x+b and one of your coordinate pairs to solve the equation for b. (Gradient is 1 not -1 by the way).

    • 2 years ago
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