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Find The equestion in slope intercept form for the line contaning the two points. (1,1 ) and ( 5,4 )

Mathematics
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|dw:1326768472676:dw|
you know how to use the equation?
that gives the gradient of the line

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Other answers:

Do You Start With Y1 Or Y2
call x_1= 1, y_1 =1, x_2=5, y_2 = 4
|dw:1326768658229:dw|
the gradient, m is 3/4
now you want the equation in the form: y=mx + c
y=mx+B
the answer is y = 3/5x -1
i did all my work the answer doesnt show up
do you get emra?
no i didnt get emra she's hard to catch o.O
you know m = 3/4. Take the first coordinate pair (1,1). Set y=1 and x=1. Then: \[1=3/4 + c\] \[c=1/4\] You can check this value by using the other coordinate pair (5,4) \[4=15/4 + c\] \[c=(16-15)/4 = 1/4\] Therefore the equation of your line is \[y=\frac{3}{4}x + \frac{1}{4}\]
it's not y=3/5x - 1 though...
thats how we learned it
oh my bad
i see my mistake
yeah its y = 3/4 x + 1/4
you forgot to minus the 1 from the 5 didn't you?
no i wrote the slope wrong -.-
imm confused alot know
5-1 is 4 right
yeah ^^ i remember when I was doing all that geometry was fun, I went to classes drunk for the lols
lol
5-1 is 4, bravo, bravo
heheheheh
How would you do this one (8,6 ( and (-3,6)
y_2 - y_1 = 6 - 6 = 0 x_2 - x_1 = -3 - 8 = -11
0 -- 11
then what do i do
it's zero yes, what does that mean about the line?
hint: m=0
?/// thats what i dont get ohh m=0 know we have to see what b=
??
go back to the general equation of a line: \[y=mx+b\] in this case, m=0 so it' just \[y=b\] This tells you that the line is a straight line forever, parallel to the x axis and intersecting the y axis at 6. Now look at your two pairs of coordinates. y is 6 in both (it better be)! So the equation of your line is......?
6 ?
6 -- 6 = 0 ??
yes \[y=6\] is the equation of your line, it's a very boring graph if you ask me
so what the equestions y=0x
yes 0x=0 for any x
so it's not in the equation
so whats the equestion then is it y=ox
remember x is a variable, and is allowed to take all values on the real line, but it obeys the law 0x=0
kk is that the equestion
k how would you do this one ( 100,-300 ) and (101,-299 )
do it how you think...
-1 ____ -1 = 1 ?
H-E-L-P
y_2-y_1 = -299 - (-300) = -299 + 300 = 1 x_2 - x_1 = 101 - 100 = 1 so it is 1/1 = 1. Your way worked too which is a good thing!
so yes, you are right
so what would the equestion bee y=-1x+ ??
use y=x+b and one of your coordinate pairs to solve the equation for b. (Gradient is 1 not -1 by the way).

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