Find The equestion in slope intercept form for the line contaning the two points. (1,1 ) and ( 5,4 )

- anonymous

Find The equestion in slope intercept form for the line contaning the two points. (1,1 ) and ( 5,4 )

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- anonymous

|dw:1326768472676:dw|

- anonymous

you know how to use the equation?

- anonymous

that gives the gradient of the line

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## More answers

- anonymous

Do You Start With Y1 Or Y2

- anonymous

call x_1= 1, y_1 =1, x_2=5, y_2 = 4

- anonymous

|dw:1326768658229:dw|

- anonymous

the gradient, m is 3/4

- anonymous

now you want the equation in the form: y=mx + c

- anonymous

y=mx+B

- anonymous

the answer is y = 3/5x -1

- anonymous

i did all my work the answer doesnt show up

- anonymous

do you get emra?

- anonymous

no i didnt get emra
she's hard to catch o.O

- anonymous

you know m = 3/4. Take the first coordinate pair (1,1). Set y=1 and x=1. Then:
\[1=3/4 + c\]
\[c=1/4\]
You can check this value by using the other coordinate pair (5,4)
\[4=15/4 + c\]
\[c=(16-15)/4 = 1/4\]
Therefore the equation of your line is
\[y=\frac{3}{4}x + \frac{1}{4}\]

- anonymous

it's not y=3/5x - 1 though...

- anonymous

thats how we learned it

- anonymous

oh my bad

- anonymous

i see my mistake

- anonymous

yeah its y = 3/4 x + 1/4

- anonymous

you forgot to minus the 1 from the 5 didn't you?

- anonymous

no i wrote the slope wrong -.-

- anonymous

imm confused alot know

- anonymous

5-1 is 4 right

- anonymous

yeah ^^ i remember when I was doing all that geometry was fun, I went to classes drunk for the lols

- anonymous

lol

- anonymous

5-1 is 4, bravo, bravo

- anonymous

heheheheh

- anonymous

How would you do this one (8,6 ( and (-3,6)

- anonymous

y_2 - y_1 = 6 - 6 = 0
x_2 - x_1 = -3 - 8 = -11

- anonymous

0
--
11

- anonymous

then what do i do

- anonymous

it's zero yes, what does that mean about the line?

- anonymous

hint: m=0

- anonymous

?/// thats what i dont get ohh m=0 know we have to see what b=

- anonymous

??

- anonymous

go back to the general equation of a line:
\[y=mx+b\]
in this case, m=0 so it' just
\[y=b\]
This tells you that the line is a straight line forever, parallel to the x axis and intersecting the y axis at 6.
Now look at your two pairs of coordinates. y is 6 in both (it better be)!
So the equation of your line is......?

- anonymous

6 ?

- anonymous

6
--
6 = 0 ??

- anonymous

yes \[y=6\] is the equation of your line, it's a very boring graph if you ask me

- anonymous

so what the equestions
y=0x

- anonymous

yes 0x=0 for any x

- anonymous

so it's not in the equation

- anonymous

so whats the equestion then is it y=ox

- anonymous

remember x is a variable, and is allowed to take all values on the real line, but it obeys the law 0x=0

- anonymous

kk is that the equestion

- anonymous

k how would you do this one ( 100,-300 ) and (101,-299 )

- anonymous

do it how you think...

- anonymous

-1
____
-1 = 1 ?

- anonymous

H-E-L-P

- anonymous

y_2-y_1 = -299 - (-300) = -299 + 300 = 1
x_2 - x_1 = 101 - 100 = 1
so it is 1/1 = 1. Your way worked too which is a good thing!

- anonymous

so yes, you are right

- anonymous

so what would the equestion bee y=-1x+ ??

- anonymous

use y=x+b and one of your coordinate pairs to solve the equation for b. (Gradient is 1 not -1 by the way).

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