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anonymous
 4 years ago
find ∫G(x,y)ds ??? , on the indicated curve
G(X,Y)=2XY, C: X=5*COST, Y=5*SINT,
0≤t≤π÷4
anonymous
 4 years ago
find ∫G(x,y)ds ??? , on the indicated curve G(X,Y)=2XY, C: X=5*COST, Y=5*SINT, 0≤t≤π÷4

This Question is Closed

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5ok i will give u a hint, u should solve it yourself :D

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5\[2 \sin(x) \cos(x)=\sin(2x)\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5so your G(x,y) =

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5\[2 \times 5 \times \cos(x) \times 5 \times \sin(x)\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5= \[25 \sin (2x)\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5you can intergerate that :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know how to find \[\int\limits_{C}^{} G(x,y) dx \] and \[\int\limits_{C}^{} G(x,y) dy \] what i want is \[\int\limits_{C}^{} G(x,y) ds \]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5one min i need to get a better help 1 second

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am thinking that i should add \[\int\limits_{C}^{} G(x,y) dx + \int\limits_{C}^{} G(x,y) dy \] but i am not sure

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3I'm sorry I'm multitasking...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is how the question written exactly ... what does he mean by ds?

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5i don't know that is why i called turing

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5ds? are u sure that is what is asking for?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer will be 125/2 .. but i do not know how to get it

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5why do you think you need to add?

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5ds generally in my questions is the area

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really i am not sure i tried everything but i could not reach the answer

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5i am waiting for turing to respond lol.. he will surely help.. i m thinking of possibilities till then

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I appreciate your help bro .. thanks.

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5no no its not done! i wont sleep till u get ur answer :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol thanks so much.. me too cuz i have to submit this assignment tomorrow :D

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3ok ds=sqrt[(dx/dt)^2+(dy/dt)^2]=5 2xy=50cost*sint got it from there?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Integrating with respect to ds means that you are integrating with respect to the arc length (which is often denoted s) of the curve C. Note that \[ds=\sqrt{dx^2+dy^2}=\sqrt{(5\cos (t) dt)^2+(5\sin (t) dt)^2}=5dt\] Thus, you have that \[\int_C G(x,y)ds=\int_0^{\pi/4}25\sin(2t)\cdot 5dt = \int_0^{\pi/4}125\sin(2t)dt = \frac{125}{2}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.5arc length is what it signifies?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.3yes, you need ds in line integrals, arc length differential

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks guys I get it .. I appreciate your help .
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