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anonymous
 4 years ago
Describe the end behavior of the graph of the polynomial function: f(x) = 2x^(5)  7x^(2)  4x
anonymous
 4 years ago
Describe the end behavior of the graph of the polynomial function: f(x) = 2x^(5)  7x^(2)  4x

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0if x is a "big" negative number then x^5 is a "huge" negative number so the graph would be in the 3rd quadrant. Similarly if x is far to the right x^5 is a huge positive number so the graph is in the first quadrant. So we say that the graph enters in the third and leaves in the first.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you! What would those points be?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know without calculating them and it doesn't matter. The question asks for the end behavior and it is as shown.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can I ask one more question? It is the same kind of question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x=0 then y=0 the graph is wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what should it look like

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use wolfram http://www.wolframalpha.com/input/?i=plot+2x^5++7x^24x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=2x^5++7x^24x+%3D+0 it has 3 real and 2 complex roots
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