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anonymous

  • 5 years ago

An object is dropped from rest and falls freely 20. meters to Earth. When is the speed of the object 9.8 meters per second?

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  1. anonymous
    • 5 years ago
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    1) during the entire first second of its fall (2) at the end of its first second of fall (3) during its entire time of fall (4) after it has fallen 9.8 meters

  2. anonymous
    • 5 years ago
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    at the end of its first second of fall

  3. anonymous
    • 5 years ago
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    v = u + at -9.8 = -9.8t t = 1 sec

  4. anonymous
    • 5 years ago
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    how so?

  5. anonymous
    • 5 years ago
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    v final velocity u initial velocity a acceleration t time free fall a = -9.8 v is negative as it is going down

  6. JamesJ
    • 5 years ago
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    Alternatively: acceleration is by definition change in velocity. Here the acceleration is is a constant, g in the downward direction. Hence of the object starts at rest and has velocity v in the downward direction at time t, then by definition \[ acceleration = \frac{v}{t} = g \] i.e., \( v = gt \) Hence \[ v = g \] when \( t = 1 \) second.

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