\[y{d^2y \over dx^2}+1=({dy \over dx})^2\]

\[y{d^2y \over dx^2}+1=({dy \over dx})^2\]

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the equation is x-absent

y y'' +1= (y')^2
(y'y)'=y'' y+ (y')^2

i can not see how you did that

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