anonymous
  • anonymous
A runner is jogging at a steady 8.4 km/hr. When the runner is 2.6 km from the finish line, a bird begins flying from the runner to the finish line at 42 km/hr (5 times as fast as the runner). When the bird reaches the finish line, it turns around and flies back to the runner. L vb vr finish line How far does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a “zero” length bird) and that it can turn without loss of speed. Answer in units of km
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Flight time of bird to finish line FL = 2.6/42 =(approx) .06hr Distance runner travels during time period = .06(8.4) = .52km Distance of runner to FL = 2.6-.52 = 2.08km Net closing speed between runner and bird = 8.4km +42 km = 50.4km Time for runner and bird to meet 2.6/50.4 = (approx) .05hr Distance covered by runner (.05)8.4 = (approx) .43 km Distance covered by bird to runner (.05)(42) = (approx) 2.1km 2.1 + 2.6 = 4.7km (its not correct) :( What am I doing wrong?
anonymous
  • anonymous
Any thoughts.
anonymous
  • anonymous
oh i hope u can help me.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Ok, the bird travels 2.6km to the finish line after it leaves the runner. The runner travels 0.52km during this time as you said. So the distance between the runner and bird (at the finish line) is 2.6-0.52=2.08km. The closing speed is 50.4km/h. Ok, the bird travels five times as fast as the runner. This means that it travels (4/5)*2.08 km in the same time that the man travels (1/5)*(2.08) km. This is where they meet. The bird travels 1.66 + 2.6=4.26km in total.
anonymous
  • anonymous
Nope that seems to be incorrect as well...
anonymous
  • anonymous
hmmmm
anonymous
  • anonymous
does it want total distance travelled or net displacement?
anonymous
  • anonymous
Net displacement would be: 0.52+ (1/5)*2.08=0.94km
anonymous
  • anonymous
it does want total distance... sorry my internet shut down for some reason.
anonymous
  • anonymous
hmmm not sure where my error is, but i'll see if I can find it

Looking for something else?

Not the answer you are looking for? Search for more explanations.