anonymous
  • anonymous
it needs to be simplified using the half angle formula i need help with sqrt 1-6x/2 how do i figure this out...
Mathematics
schrodinger
  • schrodinger
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NotTim
  • NotTim
Try using the equation editor. I might be reading the formula wrong.
anonymous
  • anonymous
no it is sqrt 1-6x/2
Mimi_x3
  • Mimi_x3
Is it: \[\sqrt{\frac{1-6x}{2}} \]

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anonymous
  • anonymous
|dw:1326780939029:dw|
anonymous
  • anonymous
i forgot the cos at first
anonymous
  • anonymous
\[\sqrt{1-\cos6x/2}\]
anonymous
  • anonymous
cos3x
anonymous
  • anonymous
the answer is suppose to be sin3x but idk how
anonymous
  • anonymous
1-cos6x=2(sin3x)^2 i made a mistake in hurry

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