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UnkleRhaukus
Group Title
Solve the following differential equation
\[(1+x^2)y''=1\]It is yabsent
 2 years ago
 2 years ago
UnkleRhaukus Group Title
Solve the following differential equation \[(1+x^2)y''=1\]It is yabsent
 2 years ago
 2 years ago

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rivermaker Group TitleBest ResponseYou've already chosen the best response.0
\[(1+x^2)y''=1 \rightarrow y'' = 1/(1+x^2)\] So just integrate twice
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
( 1+x^2) y''=1 y''= 1/(+x^2) \[y'=\tan^{1} x + C1\] C1 is constant of integration integrating above with respect to x \[y= x \tan^{1} x 1/2( \ln (x^2+1)) + C1 x+C2\]
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
THANKYOUS
 2 years ago
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