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anonymous
 4 years ago
Evaluate definite integrals using the tables of integrals
anonymous
 4 years ago
Evaluate definite integrals using the tables of integrals

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326785742825:dw

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2\[\int\limits\frac{1}{\sqrt{x^{2}+6x+10}} dx\] Then complete the square.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i will try lol if i cant then i will page u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i got the answer u tell me if it is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326786254854:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that correct mimi?

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Are you even in HS yet? O.o

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Lol No, the question is to rld

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol I am in university LOL

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2What..? university? is this uni lvl ? :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That is alright i like to be young

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol no I am in a stupid one

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Well then, we shall not be nostalgic about the past with our young minds ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am not taht old I am 20

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Lol Never saw "20" coming :P

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2lols, dont you learn that in HS? I learnt that last year :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i am learning it in calc2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well it is diffin india u guys learn alot more

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2lols, im not from india xD

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2i thought calc 2 was harder :/

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5I am in the US...Its..a 10th grade course..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is . this is the stupid stuff

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2that is 11th grade stuff for me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol idk i never learnt this in hs

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2wow, HS must be easy for you!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol we learnt diff thing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we have one math course a year and that includes e/t. algebra trig geometry and all th egood stuff

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like we odnt have algebra 1 and 2 and all that stuff

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Hmm, trig and Geo come in one pack for us.

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2same, i hate trig and geometry.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but neway this university is in the us

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ad this was one tiny sectionin calc

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0katrina so y r u up now? it is so late

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2very interesting, maths in the US, sounds so easy xD

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Depends Mimi. You have the choice to take the courses. So it varies from people.

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5It is a bit late.. Last minute procrastinator :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol zed was herer and then he left lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess it is never too late i paged u on the caht but i guess u dont read the chat

KatrinaKaif
 4 years ago
Best ResponseYou've already chosen the best response.5Only if there was an "off" button to chat...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i usually do, but the internet is a bit slow right now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so i wont hold that against u hehe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The chat is neway boring and stupid

Diyadiya
 4 years ago
Best ResponseYou've already chosen the best response.0Answer is not complete you have to find the definite integral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i just realized that :D U r right on target

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If u can solve (ln(0)+1)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, \[\int_{3}^{1}\frac{1}{\sqrt{x^{2}+6x+10}} dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya lol i dont know how to write equations lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but that wasn't my question ishaan. i want to know abt ln(0)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ln 0 isn't defined, i think you probably made some mistake

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2\[\ln(x+3+\sqrt{(x+3)^{2}+1} \] then sub 1 then 3 in

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=1%2F {\sqrt{x^{2}%2B6x%2B10}}++dx i haven't learnt hyperbolic or whatever these sinh and cosh are

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2the answer doesn't have to be in sinh

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya lol this just ln natural logarithm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk where i went wron

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, integral without putting in limits is ln( sqrt( (x + 6)^2  (Sqrt(26)^2 ) + x + 6) now you can put in the limits x^2 + 6x + 10 = (x + 6)^2  (Sqrt(26)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it gets reduced to 1 upon sqrt{x^2  a^2}

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the integral of 1 upon sqrt(x^2a^2) = log(sqrt(x^2a^2) +x)

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2\[\ln(1+3+\sqrt{(1+3)^{2}+1}  \ln(3+3+\sqrt{(3+3)^{2}+1} \] \[\ln(2+\sqrt{(4+1} ) \ln(3+3+\sqrt{0+1} )\] \[\ln(2+\sqrt{5} )\ln(0+\sqrt{1} ) = \ln(2+\sqrt{5} )\ln(1)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh wait i did wrong mimi did right i got confused in completing squares

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh thanks ishaan and mimi

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but the formula i gave you is right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ishaan that is alright Thank you for trying :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0U always come when i need u

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2np, but i think that i did it wrong somewhere :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i will recheck the steps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0who is this guest watching us?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk been here the whole time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 + 6x + 10 = x^2 + 6x + 9 9 + 10 = (x+3)^2  1 \[\log{\sqrt{x^2+ 6x+10}}+ x+3\] final answer i can't get wrong twice

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log({\sqrt{x^2+ 6x+10}}+ x+3)\]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2the final is answer is right: \[\ln(x+3+\sqrt{(x+3)^{2}+1} \] but then the end is not i think,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There are two spies now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\log{\sqrt{1  6 + 10} 1 + 3 } (\log {\sqrt{ (3)^2 + 6*3 + 10} 3 +3})\] ln(sqrt5 + 2)  ( ln(sqrt(9 18 + 10))

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2lols, people just love your question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's it, i can't be wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol ishann thankss :D

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2i think that i got the same answer, scroll up!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0two spies :O hello guest or if you don't get guest then people who don't have an account or don't wanna sign in

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.2they are just too lazy to sign up for an account :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or they wanna spy on us

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ln(sqrt(5) + 2) us the final answer the other one gets to zero

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0brb lunch time instant noodles yumm :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0going to bed it is 4 am

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks diya for reminding me
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