anonymous
  • anonymous
Evaluate definite integrals using the tables of integrals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1326785742825:dw|
Mimi_x3
  • Mimi_x3
\[\int\limits\frac{1}{\sqrt{x^{2}+6x+10}} dx\] Then complete the square.
anonymous
  • anonymous
oh ya thanks

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More answers

Mimi_x3
  • Mimi_x3
can you do it?
anonymous
  • anonymous
well i will try lol if i cant then i will page u
anonymous
  • anonymous
ok i got the answer u tell me if it is correct
anonymous
  • anonymous
|dw:1326786254854:dw|
anonymous
  • anonymous
is that correct mimi?
Diyadiya
  • Diyadiya
Right ! :)
anonymous
  • anonymous
Hey thanks diya/lena
anonymous
  • anonymous
:D
Diyadiya
  • Diyadiya
*Diya :D
KatrinaKaif
  • KatrinaKaif
Are you even in HS yet? O.o
Diyadiya
  • Diyadiya
WHo me?
anonymous
  • anonymous
who me?
anonymous
  • anonymous
that pic is of lena
KatrinaKaif
  • KatrinaKaif
Lol No, the question is to rld
anonymous
  • anonymous
lol I am in university LOL
KatrinaKaif
  • KatrinaKaif
My apologizes!
Mimi_x3
  • Mimi_x3
What..? university? is this uni lvl ? :/
anonymous
  • anonymous
That is alright i like to be young
anonymous
  • anonymous
lol no I am in a stupid one
KatrinaKaif
  • KatrinaKaif
Well then, we shall not be nostalgic about the past with our young minds ;)
anonymous
  • anonymous
i am not taht old I am 20
KatrinaKaif
  • KatrinaKaif
Lol Never saw "20" coming :P
Mimi_x3
  • Mimi_x3
lols, dont you learn that in HS? I learnt that last year :/
anonymous
  • anonymous
lol i am learning it in calc2
anonymous
  • anonymous
well it is diffin india u guys learn alot more
Mimi_x3
  • Mimi_x3
lols, im not from india xD
anonymous
  • anonymous
so where ru from?
Mimi_x3
  • Mimi_x3
i thought calc 2 was harder :/
KatrinaKaif
  • KatrinaKaif
I am in the US...Its..a 10th grade course..
Mimi_x3
  • Mimi_x3
Australia.
anonymous
  • anonymous
it is . this is the stupid stuff
Mimi_x3
  • Mimi_x3
that is 11th grade stuff for me.
anonymous
  • anonymous
lol idk i never learnt this in hs
KatrinaKaif
  • KatrinaKaif
Ah I see Coolio
Mimi_x3
  • Mimi_x3
wow, HS must be easy for you!
anonymous
  • anonymous
lol we learnt diff thing
anonymous
  • anonymous
we have one math course a year and that includes e/t. algebra trig geometry and all th egood stuff
anonymous
  • anonymous
like we odnt have algebra 1 and 2 and all that stuff
KatrinaKaif
  • KatrinaKaif
Hmm, trig and Geo come in one pack for us.
Mimi_x3
  • Mimi_x3
same, i hate trig and geometry.
anonymous
  • anonymous
but neway this university is in the us
anonymous
  • anonymous
ad this was one tiny sectionin calc
KatrinaKaif
  • KatrinaKaif
Interesting..
anonymous
  • anonymous
katrina so y r u up now? it is so late
Mimi_x3
  • Mimi_x3
very interesting, maths in the US, sounds so easy xD
anonymous
  • anonymous
lol i am from canada
KatrinaKaif
  • KatrinaKaif
Depends Mimi. You have the choice to take the courses. So it varies from people.
KatrinaKaif
  • KatrinaKaif
It is a bit late.. Last minute procrastinator :P
anonymous
  • anonymous
lol zed was herer and then he left lol
anonymous
  • anonymous
i'm back :)
anonymous
  • anonymous
lol
KatrinaKaif
  • KatrinaKaif
Wb
anonymous
  • anonymous
I guess it is never too late i paged u on the caht but i guess u dont read the chat
KatrinaKaif
  • KatrinaKaif
Only if there was an "off" button to chat...
anonymous
  • anonymous
i usually do, but the internet is a bit slow right now
anonymous
  • anonymous
ok so i wont hold that against u hehe
anonymous
  • anonymous
The chat is neway boring and stupid
Diyadiya
  • Diyadiya
Answer is not complete you have to find the definite integral
anonymous
  • anonymous
lol i just realized that :D U r right on target
anonymous
  • anonymous
Hey wld anyone know?
anonymous
  • anonymous
If u can solve (ln(0)+1)?
anonymous
  • anonymous
ln(0) is undefined
anonymous
  • anonymous
Okay, \[\int_{-3}^{-1}\frac{1}{\sqrt{x^{2}+6x+10}} dx\]
anonymous
  • anonymous
ya lol i dont know how to write equations lol
anonymous
  • anonymous
but that wasn't my question ishaan. i want to know abt ln(0)
anonymous
  • anonymous
ln 0 isn't defined, i think you probably made some mistake
Mimi_x3
  • Mimi_x3
\[\ln(x+3+\sqrt{(x+3)^{2}+1} \] then sub -1 then -3 in
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=1%2F{\sqrt{x^{2}%2B6x%2B10}}++dx i haven't learnt hyperbolic or whatever these sinh and cosh are
anonymous
  • anonymous
rld? are you here
Mimi_x3
  • Mimi_x3
the answer doesn't have to be in sinh
anonymous
  • anonymous
ya lol this just ln natural logarithm
anonymous
  • anonymous
idk where i went wron
anonymous
  • anonymous
ln(-3+3)=ln(o)
anonymous
  • anonymous
okay, integral without putting in limits is ln( sqrt( (x + 6)^2 - (Sqrt(26)^2 ) + x + 6) now you can put in the limits x^2 + 6x + 10 = (x + 6)^2 - (Sqrt(26)^2
anonymous
  • anonymous
it gets reduced to 1 upon sqrt{x^2 - a^2}
anonymous
  • anonymous
the integral of 1 upon sqrt(x^2-a^2) = log(sqrt(x^2-a^2) +x)
Mimi_x3
  • Mimi_x3
\[\ln(-1+3+\sqrt{(-1+3)^{2}+1} - \ln(-3+3+\sqrt{(-3+3)^{2}+1} \] \[\ln(2+\sqrt{(4+1} )- \ln(-3+3+\sqrt{0+1} )\] \[\ln(2+\sqrt{5} )-\ln(0+\sqrt{1} ) = \ln(2+\sqrt{5} )-\ln(1)\]
anonymous
  • anonymous
oh wait i did wrong mimi did right i got confused in completing squares
anonymous
  • anonymous
oh thanks ishaan and mimi
anonymous
  • anonymous
but the formula i gave you is right
anonymous
  • anonymous
Ishaan that is alright Thank you for trying :D
anonymous
  • anonymous
U always come when i need u
anonymous
  • anonymous
Thanks mimi
Mimi_x3
  • Mimi_x3
np, but i think that i did it wrong somewhere :/
anonymous
  • anonymous
lol i will recheck the steps
anonymous
  • anonymous
who is this guest watching us?
anonymous
  • anonymous
hello guest!
anonymous
  • anonymous
idk been here the whole time
anonymous
  • anonymous
spying u ishaan
anonymous
  • anonymous
x^2 + 6x + 10 = x^2 + 6x + 9 -9 + 10 = (x+3)^2 - 1 \[\log{\sqrt{x^2+ 6x+10}}+ x+3\] final answer i can't get wrong twice
anonymous
  • anonymous
\[\log({\sqrt{x^2+ 6x+10}}+ x+3)\]
anonymous
  • anonymous
yeah, a spy
Mimi_x3
  • Mimi_x3
the final is answer is right: \[\ln(x+3+\sqrt{(x+3)^{2}+1} \] but then the end is not i think,
anonymous
  • anonymous
k i will recheck it
anonymous
  • anonymous
There are two spies now
anonymous
  • anonymous
\[\log{\sqrt{1 - 6 + 10} -1 + 3 } -(\log {\sqrt{ (-3)^2 + -6*3 + 10} -3 +3})\] ln(sqrt5 + 2) - ( ln(sqrt(9 -18 + 10))
Mimi_x3
  • Mimi_x3
lols, people just love your question.
anonymous
  • anonymous
that's it, i can't be wrong
anonymous
  • anonymous
lol ishann thankss :D
Mimi_x3
  • Mimi_x3
i think that i got the same answer, scroll up!
anonymous
  • anonymous
two spies :-O hello guest or if you don't get guest then people who don't have an account or don't wanna sign in
Mimi_x3
  • Mimi_x3
they are just too lazy to sign up for an account :P
anonymous
  • anonymous
or they wanna spy on us
anonymous
  • anonymous
ln(sqrt(5) + 2) us the final answer the other one gets to zero
anonymous
  • anonymous
is* not us :-D
anonymous
  • anonymous
seems legit :-D
anonymous
  • anonymous
brb lunch time instant noodles yumm :-D
anonymous
  • anonymous
ya got that thanks
anonymous
  • anonymous
you're welcome
anonymous
  • anonymous
going to bed it is 4 am
anonymous
  • anonymous
bye mimi
anonymous
  • anonymous
sweet dreams
anonymous
  • anonymous
lol
Diyadiya
  • Diyadiya
LoL
anonymous
  • anonymous
Thanks diya for reminding me
Diyadiya
  • Diyadiya
NoProblem (:

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