Evaluate definite integrals using the tables of integrals

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Evaluate definite integrals using the tables of integrals

Mathematics
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|dw:1326785742825:dw|
\[\int\limits\frac{1}{\sqrt{x^{2}+6x+10}} dx\] Then complete the square.
oh ya thanks

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Other answers:

can you do it?
well i will try lol if i cant then i will page u
ok i got the answer u tell me if it is correct
|dw:1326786254854:dw|
is that correct mimi?
Right ! :)
Hey thanks diya/lena
:D
*Diya :D
Are you even in HS yet? O.o
WHo me?
who me?
that pic is of lena
Lol No, the question is to rld
lol I am in university LOL
My apologizes!
What..? university? is this uni lvl ? :/
That is alright i like to be young
lol no I am in a stupid one
Well then, we shall not be nostalgic about the past with our young minds ;)
i am not taht old I am 20
Lol Never saw "20" coming :P
lols, dont you learn that in HS? I learnt that last year :/
lol i am learning it in calc2
well it is diffin india u guys learn alot more
lols, im not from india xD
so where ru from?
i thought calc 2 was harder :/
I am in the US...Its..a 10th grade course..
Australia.
it is . this is the stupid stuff
that is 11th grade stuff for me.
lol idk i never learnt this in hs
Ah I see Coolio
wow, HS must be easy for you!
lol we learnt diff thing
we have one math course a year and that includes e/t. algebra trig geometry and all th egood stuff
like we odnt have algebra 1 and 2 and all that stuff
Hmm, trig and Geo come in one pack for us.
same, i hate trig and geometry.
but neway this university is in the us
ad this was one tiny sectionin calc
Interesting..
katrina so y r u up now? it is so late
very interesting, maths in the US, sounds so easy xD
lol i am from canada
Depends Mimi. You have the choice to take the courses. So it varies from people.
It is a bit late.. Last minute procrastinator :P
lol zed was herer and then he left lol
i'm back :)
lol
Wb
I guess it is never too late i paged u on the caht but i guess u dont read the chat
Only if there was an "off" button to chat...
i usually do, but the internet is a bit slow right now
ok so i wont hold that against u hehe
The chat is neway boring and stupid
Answer is not complete you have to find the definite integral
lol i just realized that :D U r right on target
Hey wld anyone know?
If u can solve (ln(0)+1)?
ln(0) is undefined
Okay, \[\int_{-3}^{-1}\frac{1}{\sqrt{x^{2}+6x+10}} dx\]
ya lol i dont know how to write equations lol
but that wasn't my question ishaan. i want to know abt ln(0)
ln 0 isn't defined, i think you probably made some mistake
\[\ln(x+3+\sqrt{(x+3)^{2}+1} \] then sub -1 then -3 in
http://www.wolframalpha.com/input/?i=1%2F{\sqrt{x^{2}%2B6x%2B10}}++dx i haven't learnt hyperbolic or whatever these sinh and cosh are
rld? are you here
the answer doesn't have to be in sinh
ya lol this just ln natural logarithm
idk where i went wron
ln(-3+3)=ln(o)
okay, integral without putting in limits is ln( sqrt( (x + 6)^2 - (Sqrt(26)^2 ) + x + 6) now you can put in the limits x^2 + 6x + 10 = (x + 6)^2 - (Sqrt(26)^2
it gets reduced to 1 upon sqrt{x^2 - a^2}
the integral of 1 upon sqrt(x^2-a^2) = log(sqrt(x^2-a^2) +x)
\[\ln(-1+3+\sqrt{(-1+3)^{2}+1} - \ln(-3+3+\sqrt{(-3+3)^{2}+1} \] \[\ln(2+\sqrt{(4+1} )- \ln(-3+3+\sqrt{0+1} )\] \[\ln(2+\sqrt{5} )-\ln(0+\sqrt{1} ) = \ln(2+\sqrt{5} )-\ln(1)\]
oh wait i did wrong mimi did right i got confused in completing squares
oh thanks ishaan and mimi
but the formula i gave you is right
Ishaan that is alright Thank you for trying :D
U always come when i need u
Thanks mimi
np, but i think that i did it wrong somewhere :/
lol i will recheck the steps
who is this guest watching us?
hello guest!
idk been here the whole time
spying u ishaan
x^2 + 6x + 10 = x^2 + 6x + 9 -9 + 10 = (x+3)^2 - 1 \[\log{\sqrt{x^2+ 6x+10}}+ x+3\] final answer i can't get wrong twice
\[\log({\sqrt{x^2+ 6x+10}}+ x+3)\]
yeah, a spy
the final is answer is right: \[\ln(x+3+\sqrt{(x+3)^{2}+1} \] but then the end is not i think,
k i will recheck it
There are two spies now
\[\log{\sqrt{1 - 6 + 10} -1 + 3 } -(\log {\sqrt{ (-3)^2 + -6*3 + 10} -3 +3})\] ln(sqrt5 + 2) - ( ln(sqrt(9 -18 + 10))
lols, people just love your question.
that's it, i can't be wrong
lol ishann thankss :D
i think that i got the same answer, scroll up!
two spies :-O hello guest or if you don't get guest then people who don't have an account or don't wanna sign in
they are just too lazy to sign up for an account :P
or they wanna spy on us
ln(sqrt(5) + 2) us the final answer the other one gets to zero
is* not us :-D
seems legit :-D
brb lunch time instant noodles yumm :-D
ya got that thanks
you're welcome
going to bed it is 4 am
bye mimi
sweet dreams
lol
LoL
Thanks diya for reminding me
NoProblem (:

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