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anonymous

  • 5 years ago

Evaluate definite integrals using the tables of integrals

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  1. anonymous
    • 5 years ago
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    |dw:1326785742825:dw|

  2. Mimi_x3
    • 5 years ago
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    \[\int\limits\frac{1}{\sqrt{x^{2}+6x+10}} dx\] Then complete the square.

  3. anonymous
    • 5 years ago
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    oh ya thanks

  4. Mimi_x3
    • 5 years ago
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    can you do it?

  5. anonymous
    • 5 years ago
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    well i will try lol if i cant then i will page u

  6. anonymous
    • 5 years ago
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    ok i got the answer u tell me if it is correct

  7. anonymous
    • 5 years ago
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    |dw:1326786254854:dw|

  8. anonymous
    • 5 years ago
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    is that correct mimi?

  9. Diyadiya
    • 5 years ago
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    Right ! :)

  10. anonymous
    • 5 years ago
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    Hey thanks diya/lena

  11. anonymous
    • 5 years ago
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    :D

  12. Diyadiya
    • 5 years ago
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    *Diya :D

  13. KatrinaKaif
    • 5 years ago
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    Are you even in HS yet? O.o

  14. Diyadiya
    • 5 years ago
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    WHo me?

  15. anonymous
    • 5 years ago
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    who me?

  16. anonymous
    • 5 years ago
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    that pic is of lena

  17. KatrinaKaif
    • 5 years ago
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    Lol No, the question is to rld

  18. anonymous
    • 5 years ago
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    lol I am in university LOL

  19. KatrinaKaif
    • 5 years ago
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    My apologizes!

  20. Mimi_x3
    • 5 years ago
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    What..? university? is this uni lvl ? :/

  21. anonymous
    • 5 years ago
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    That is alright i like to be young

  22. anonymous
    • 5 years ago
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    lol no I am in a stupid one

  23. KatrinaKaif
    • 5 years ago
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    Well then, we shall not be nostalgic about the past with our young minds ;)

  24. anonymous
    • 5 years ago
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    i am not taht old I am 20

  25. KatrinaKaif
    • 5 years ago
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    Lol Never saw "20" coming :P

  26. Mimi_x3
    • 5 years ago
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    lols, dont you learn that in HS? I learnt that last year :/

  27. anonymous
    • 5 years ago
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    lol i am learning it in calc2

  28. anonymous
    • 5 years ago
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    well it is diffin india u guys learn alot more

  29. Mimi_x3
    • 5 years ago
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    lols, im not from india xD

  30. anonymous
    • 5 years ago
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    so where ru from?

  31. Mimi_x3
    • 5 years ago
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    i thought calc 2 was harder :/

  32. KatrinaKaif
    • 5 years ago
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    I am in the US...Its..a 10th grade course..

  33. Mimi_x3
    • 5 years ago
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    Australia.

  34. anonymous
    • 5 years ago
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    it is . this is the stupid stuff

  35. Mimi_x3
    • 5 years ago
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    that is 11th grade stuff for me.

  36. anonymous
    • 5 years ago
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    lol idk i never learnt this in hs

  37. KatrinaKaif
    • 5 years ago
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    Ah I see Coolio

  38. Mimi_x3
    • 5 years ago
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    wow, HS must be easy for you!

  39. anonymous
    • 5 years ago
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    lol we learnt diff thing

  40. anonymous
    • 5 years ago
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    we have one math course a year and that includes e/t. algebra trig geometry and all th egood stuff

  41. anonymous
    • 5 years ago
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    like we odnt have algebra 1 and 2 and all that stuff

  42. KatrinaKaif
    • 5 years ago
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    Hmm, trig and Geo come in one pack for us.

  43. Mimi_x3
    • 5 years ago
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    same, i hate trig and geometry.

  44. anonymous
    • 5 years ago
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    but neway this university is in the us

  45. anonymous
    • 5 years ago
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    ad this was one tiny sectionin calc

  46. KatrinaKaif
    • 5 years ago
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    Interesting..

  47. anonymous
    • 5 years ago
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    katrina so y r u up now? it is so late

  48. Mimi_x3
    • 5 years ago
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    very interesting, maths in the US, sounds so easy xD

  49. anonymous
    • 5 years ago
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    lol i am from canada

  50. KatrinaKaif
    • 5 years ago
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    Depends Mimi. You have the choice to take the courses. So it varies from people.

  51. KatrinaKaif
    • 5 years ago
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    It is a bit late.. Last minute procrastinator :P

  52. anonymous
    • 5 years ago
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    lol zed was herer and then he left lol

  53. anonymous
    • 5 years ago
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    i'm back :)

  54. anonymous
    • 5 years ago
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    lol

  55. KatrinaKaif
    • 5 years ago
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    Wb

  56. anonymous
    • 5 years ago
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    I guess it is never too late i paged u on the caht but i guess u dont read the chat

  57. KatrinaKaif
    • 5 years ago
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    Only if there was an "off" button to chat...

  58. anonymous
    • 5 years ago
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    i usually do, but the internet is a bit slow right now

  59. anonymous
    • 5 years ago
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    ok so i wont hold that against u hehe

  60. anonymous
    • 5 years ago
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    The chat is neway boring and stupid

  61. Diyadiya
    • 5 years ago
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    Answer is not complete you have to find the definite integral

  62. anonymous
    • 5 years ago
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    lol i just realized that :D U r right on target

  63. anonymous
    • 5 years ago
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    Hey wld anyone know?

  64. anonymous
    • 5 years ago
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    If u can solve (ln(0)+1)?

  65. anonymous
    • 5 years ago
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    ln(0) is undefined

  66. anonymous
    • 5 years ago
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    Okay, \[\int_{-3}^{-1}\frac{1}{\sqrt{x^{2}+6x+10}} dx\]

  67. anonymous
    • 5 years ago
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    ya lol i dont know how to write equations lol

  68. anonymous
    • 5 years ago
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    but that wasn't my question ishaan. i want to know abt ln(0)

  69. anonymous
    • 5 years ago
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    ln 0 isn't defined, i think you probably made some mistake

  70. Mimi_x3
    • 5 years ago
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    \[\ln(x+3+\sqrt{(x+3)^{2}+1} \] then sub -1 then -3 in

  71. anonymous
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=1%2F {\sqrt{x^{2}%2B6x%2B10}}++dx i haven't learnt hyperbolic or whatever these sinh and cosh are

  72. anonymous
    • 5 years ago
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    rld? are you here

  73. Mimi_x3
    • 5 years ago
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    the answer doesn't have to be in sinh

  74. anonymous
    • 5 years ago
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    ya lol this just ln natural logarithm

  75. anonymous
    • 5 years ago
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    idk where i went wron

  76. anonymous
    • 5 years ago
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    ln(-3+3)=ln(o)

  77. anonymous
    • 5 years ago
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    okay, integral without putting in limits is ln( sqrt( (x + 6)^2 - (Sqrt(26)^2 ) + x + 6) now you can put in the limits x^2 + 6x + 10 = (x + 6)^2 - (Sqrt(26)^2

  78. anonymous
    • 5 years ago
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    it gets reduced to 1 upon sqrt{x^2 - a^2}

  79. anonymous
    • 5 years ago
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    the integral of 1 upon sqrt(x^2-a^2) = log(sqrt(x^2-a^2) +x)

  80. Mimi_x3
    • 5 years ago
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    \[\ln(-1+3+\sqrt{(-1+3)^{2}+1} - \ln(-3+3+\sqrt{(-3+3)^{2}+1} \] \[\ln(2+\sqrt{(4+1} )- \ln(-3+3+\sqrt{0+1} )\] \[\ln(2+\sqrt{5} )-\ln(0+\sqrt{1} ) = \ln(2+\sqrt{5} )-\ln(1)\]

  81. anonymous
    • 5 years ago
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    oh wait i did wrong mimi did right i got confused in completing squares

  82. anonymous
    • 5 years ago
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    oh thanks ishaan and mimi

  83. anonymous
    • 5 years ago
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    but the formula i gave you is right

  84. anonymous
    • 5 years ago
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    Ishaan that is alright Thank you for trying :D

  85. anonymous
    • 5 years ago
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    U always come when i need u

  86. anonymous
    • 5 years ago
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    Thanks mimi

  87. Mimi_x3
    • 5 years ago
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    np, but i think that i did it wrong somewhere :/

  88. anonymous
    • 5 years ago
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    lol i will recheck the steps

  89. anonymous
    • 5 years ago
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    who is this guest watching us?

  90. anonymous
    • 5 years ago
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    hello guest!

  91. anonymous
    • 5 years ago
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    idk been here the whole time

  92. anonymous
    • 5 years ago
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    spying u ishaan

  93. anonymous
    • 5 years ago
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    x^2 + 6x + 10 = x^2 + 6x + 9 -9 + 10 = (x+3)^2 - 1 \[\log{\sqrt{x^2+ 6x+10}}+ x+3\] final answer i can't get wrong twice

  94. anonymous
    • 5 years ago
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    \[\log({\sqrt{x^2+ 6x+10}}+ x+3)\]

  95. anonymous
    • 5 years ago
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    yeah, a spy

  96. Mimi_x3
    • 5 years ago
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    the final is answer is right: \[\ln(x+3+\sqrt{(x+3)^{2}+1} \] but then the end is not i think,

  97. anonymous
    • 5 years ago
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    k i will recheck it

  98. anonymous
    • 5 years ago
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    There are two spies now

  99. anonymous
    • 5 years ago
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    \[\log{\sqrt{1 - 6 + 10} -1 + 3 } -(\log {\sqrt{ (-3)^2 + -6*3 + 10} -3 +3})\] ln(sqrt5 + 2) - ( ln(sqrt(9 -18 + 10))

  100. Mimi_x3
    • 5 years ago
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    lols, people just love your question.

  101. anonymous
    • 5 years ago
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    that's it, i can't be wrong

  102. anonymous
    • 5 years ago
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    lol ishann thankss :D

  103. Mimi_x3
    • 5 years ago
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    i think that i got the same answer, scroll up!

  104. anonymous
    • 5 years ago
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    two spies :-O hello guest or if you don't get guest then people who don't have an account or don't wanna sign in

  105. Mimi_x3
    • 5 years ago
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    they are just too lazy to sign up for an account :P

  106. anonymous
    • 5 years ago
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    or they wanna spy on us

  107. anonymous
    • 5 years ago
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    ln(sqrt(5) + 2) us the final answer the other one gets to zero

  108. anonymous
    • 5 years ago
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    is* not us :-D

  109. anonymous
    • 5 years ago
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    seems legit :-D

  110. anonymous
    • 5 years ago
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    brb lunch time instant noodles yumm :-D

  111. anonymous
    • 5 years ago
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    ya got that thanks

  112. anonymous
    • 5 years ago
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    you're welcome

  113. anonymous
    • 5 years ago
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    going to bed it is 4 am

  114. anonymous
    • 5 years ago
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    bye mimi

  115. anonymous
    • 5 years ago
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    sweet dreams

  116. anonymous
    • 5 years ago
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    lol

  117. Diyadiya
    • 5 years ago
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    LoL

  118. anonymous
    • 5 years ago
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    Thanks diya for reminding me

  119. Diyadiya
    • 5 years ago
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    NoProblem (:

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