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Denebel Group TitleBest ResponseYou've already chosen the best response.1
dw:1326787674889:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
I tried using u=x? What should u be? dw:1326787713147:dw
 2 years ago

imperialist Group TitleBest ResponseYou've already chosen the best response.3
Hint: what do you get when you take the derivative of \[\cot x = \frac{\cos x}{\sin x}\]
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Derivative of cot x? =(arccsc x)^2
 2 years ago

imperialist Group TitleBest ResponseYou've already chosen the best response.3
Not arccsc, but rather \[\csc^2 x = \frac{1}{\sin^2x}\]
 2 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.1
dw:1326788429512:dw
 2 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.1
dw:1326788552348:dw
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Oh yes, my bad. So.. dw:1326788533509:dw ?
 2 years ago

Denebel Group TitleBest ResponseYou've already chosen the best response.1
Where did the neg. come from?
 2 years ago

imperialist Group TitleBest ResponseYou've already chosen the best response.3
\[\int \frac{3 dx}{\sin^2x}=3\int \csc^2xdx = 3(\cot x)+C=3\cot x + C\]
 2 years ago

DHASHNI Group TitleBest ResponseYou've already chosen the best response.1
if we integrate cosec^2 x =>cot x
 2 years ago
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