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Rath111
 5 years ago
Anyone with the knowledge on how to do [(ax)/(ab)] 2 = (cx)/(bc)? Stuck on this problem in my HW and I need to solve to find x...
Rath111
 5 years ago
Anyone with the knowledge on how to do [(ax)/(ab)] 2 = (cx)/(bc)? Stuck on this problem in my HW and I need to solve to find x...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ax}{ab}  2 = \frac{cx}{bc}\] \[\frac{(bc)(ax)}{ab}  2(bc) = cx\] \[\frac{(bc)(ax)}{ab} + (xc) = 2(bc)\] \[abbxac+cx + (xc)(ab) = 2(bc)(ab)\] \[x(cb+ab) + ab ac ac+bc = 2(ab b^2ac+bc)\] \[x(a2b+c) = 2(ab b^2ac+bc)  ab +2ac bc\] \[x(a2b+c) = ab  2b^2 +bc\] \[x=\frac{b(a2b+c)}{(a2b+c)} = b\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry tat last bit is this: \[x=\frac{b(a2b^2+c)}{(a2b+c)}\]

Rath111
 5 years ago
Best ResponseYou've already chosen the best response.0The book says the answer is x=b.. So i'm confused as hell.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try \[\frac{ax}{ab}  2 = \frac{cx}{bc}\] \[\frac{ax}{ab}  \frac{cx}{bc} = 2\] \[(ax)(bc)  (ab)(cx) = 2(ab)(bc)\] \[ab ac bx + cx ac+ax+bcbx = 2ab2ac2b^2+2bc\] \[x(cb+ab) +ab 2ac + bc= 2ab2ac2b^2+2bc\] \[x(a2b+c) = ab 2b^2+bc\] \[x(a2b+c) = b(a2b+c)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then just divide by (a2b+c)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL I factored it wrong at the very end  lapse o concentration obviously

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my first answer was right. sorry about doing it twice lol
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