pokemon23
  • pokemon23
anyone to help?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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pokemon23
  • pokemon23
|dw:1326804880717:dw|
Diyadiya
  • Diyadiya
\[\sqrt{48} ?\]
pokemon23
  • pokemon23
|dw:1326804895482:dw|

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More answers

Diyadiya
  • Diyadiya
Nope
pokemon23
  • pokemon23
|dw:1326805008004:dw|
anonymous
  • anonymous
\[4\sqrt{3}\]
Diyadiya
  • Diyadiya
\[\sqrt{6} \times \sqrt{8}= \sqrt{3} \times \sqrt{2} * \sqrt{2} \times \sqrt{2} \times \sqrt 2\]
pokemon23
  • pokemon23
ok but how do you get 4?
Diyadiya
  • Diyadiya
\[\sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} = 2 \times 2 =4\]
anonymous
  • anonymous
3 * 16 = 48
pokemon23
  • pokemon23
can you explain why you get 4? I see the picture I just want to know is their like an exact rule or explanation in why you got 4?
Diyadiya
  • Diyadiya
ok
pokemon23
  • pokemon23
ty
Diyadiya
  • Diyadiya
|dw:1326805321308:dw|
Diyadiya
  • Diyadiya
\[\sqrt{2} \times \sqrt{2}=(\sqrt{2})^2=2\]
Diyadiya
  • Diyadiya
theres a mistake
anonymous
  • anonymous
\[\sqrt{3 * 16} = 4\sqrt{3}\]
Diyadiya
  • Diyadiya
|dw:1326805573193:dw|
anonymous
  • anonymous
|dw:1326805832186:dw|
Diyadiya
  • Diyadiya
|dw:1326805779575:dw|

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