anonymous
  • anonymous
The total number of ways one can arrange 5 math books, 3 physics books, and 2 statistics books on a bookshelf, if no 2 books of the same subject can be placed next to each other, is...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
assume the books within each subject are distinct from each other
anonymous
  • anonymous
hold on im looking at it
anonymous
  • anonymous
10!

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anonymous
  • anonymous
5choose2 times 2factorial
anonymous
  • anonymous
just 5 choose 2
anonymous
  • anonymous
k
anonymous
  • anonymous
you still there 2be?
anonymous
  • anonymous
alright will u be on for the next 5 mins or so
anonymous
  • anonymous
k thanks
anonymous
  • anonymous
what does 5 permute one mean in words
anonymous
  • anonymous
k im doing it by thinking of it as slots
anonymous
  • anonymous
i get 1200 ways
anonymous
  • anonymous
(5!*5!)/(3!*2!) = 1200
phi
  • phi
Here's my shot at it
phi
  • phi
1 Attachment
anonymous
  • anonymous
ok this is my reasoning
anonymous
  • anonymous
the only way such a arrangement can be possible is if all the math books are spaced out so there are 2 possible ways this can happen, that the 10 slots start with a math book or end with a math book giving us a total of 5! * 2
anonymous
  • anonymous
then , the remaining 5 slots in between the math books can be taken by the 5 other books in any order
anonymous
  • anonymous
so to correct myself its 5!*5!*2
anonymous
  • anonymous
28800
anonymous
  • anonymous
hey wait phi is right
anonymous
  • anonymous
i missed out on some other possibilities

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