The total number of ways one can arrange 5 math books, 3 physics books, and 2 statistics books on a bookshelf, if no 2 books of the same subject can be placed next to each other, is...

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The total number of ways one can arrange 5 math books, 3 physics books, and 2 statistics books on a bookshelf, if no 2 books of the same subject can be placed next to each other, is...

Mathematics
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assume the books within each subject are distinct from each other
hold on im looking at it
10!

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Other answers:

5choose2 times 2factorial
just 5 choose 2
k
you still there 2be?
alright will u be on for the next 5 mins or so
k thanks
what does 5 permute one mean in words
k im doing it by thinking of it as slots
i get 1200 ways
(5!*5!)/(3!*2!) = 1200
  • phi
Here's my shot at it
  • phi
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ok this is my reasoning
the only way such a arrangement can be possible is if all the math books are spaced out so there are 2 possible ways this can happen, that the 10 slots start with a math book or end with a math book giving us a total of 5! * 2
then , the remaining 5 slots in between the math books can be taken by the 5 other books in any order
so to correct myself its 5!*5!*2
28800
hey wait phi is right
i missed out on some other possibilities

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