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anonymous

  • 5 years ago

The total number of ways one can arrange 5 math books, 3 physics books, and 2 statistics books on a bookshelf, if no 2 books of the same subject can be placed next to each other, is...

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  1. anonymous
    • 5 years ago
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    assume the books within each subject are distinct from each other

  2. anonymous
    • 5 years ago
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    hold on im looking at it

  3. anonymous
    • 5 years ago
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    10!

  4. anonymous
    • 5 years ago
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    5choose2 times 2factorial

  5. anonymous
    • 5 years ago
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    just 5 choose 2

  6. anonymous
    • 5 years ago
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    k

  7. anonymous
    • 5 years ago
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    you still there 2be?

  8. anonymous
    • 5 years ago
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    alright will u be on for the next 5 mins or so

  9. anonymous
    • 5 years ago
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    k thanks

  10. anonymous
    • 5 years ago
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    what does 5 permute one mean in words

  11. anonymous
    • 5 years ago
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    k im doing it by thinking of it as slots

  12. anonymous
    • 5 years ago
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    i get 1200 ways

  13. anonymous
    • 5 years ago
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    (5!*5!)/(3!*2!) = 1200

  14. phi
    • 5 years ago
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    Here's my shot at it

  15. phi
    • 5 years ago
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  16. anonymous
    • 5 years ago
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    ok this is my reasoning

  17. anonymous
    • 5 years ago
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    the only way such a arrangement can be possible is if all the math books are spaced out so there are 2 possible ways this can happen, that the 10 slots start with a math book or end with a math book giving us a total of 5! * 2

  18. anonymous
    • 5 years ago
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    then , the remaining 5 slots in between the math books can be taken by the 5 other books in any order

  19. anonymous
    • 5 years ago
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    so to correct myself its 5!*5!*2

  20. anonymous
    • 5 years ago
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    28800

  21. anonymous
    • 5 years ago
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    hey wait phi is right

  22. anonymous
    • 5 years ago
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    i missed out on some other possibilities

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spraguer (Moderator)
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