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anonymous
 5 years ago
What are the possible number of positive real, negative real, and complex zeros of
f(x) = 6x3 – 3x2 + 5x + 9?
Answer:
A)Positive Real: 1
Negative Real: 0
Complex: 2
B)Positive Real: 2 or 0
Negative Real: 2 or 0
Complex: 1
C)Positive Real: 2 or 0
Negative Real: 1
Complex: 2 or 0
D)Positive Real: 1
Negative Real: 2 or 0
Complex: 2 or 0
Help me please:)))
anonymous
 5 years ago
What are the possible number of positive real, negative real, and complex zeros of f(x) = 6x3 – 3x2 + 5x + 9? Answer: A)Positive Real: 1 Negative Real: 0 Complex: 2 B)Positive Real: 2 or 0 Negative Real: 2 or 0 Complex: 1 C)Positive Real: 2 or 0 Negative Real: 1 Complex: 2 or 0 D)Positive Real: 1 Negative Real: 2 or 0 Complex: 2 or 0 Help me please:)))

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.7+6x3 3x2 +5x +9 1  1  0  sign changes twice, which means there is either 2 or 0 positives swap the signs of the odd powers: 6x3 3x2 5x +9 1  0  signs changes once; there is at elast 1 negative solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha yeah i kinda got tht from you explaining it, thank you very much:)))
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