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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0since sec^2 is the derivaive of tan, this is a simple enough arrangement: \[\int f(u)du\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0i thinkk you might be off by a 4 tho

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0x/4 pops out a spurious little 1/4 that missing

shinigami1m
 3 years ago
Best ResponseYou've already chosen the best response.1is 2pi/3 to pi = to pi to 2pi/3 ???

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0then given the interval [a,b] you work it out: F(b)F(a)

shinigami1m
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1326817635699:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[[tan^4(\frac{1}{4}x)]'=\frac{1}{4}tan^3(\frac{1}{4}x)sec^2(\frac{1}{4}x)\] so we have to multiply thru by 4 to begin with

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1326817802065:dw

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1\[u=\frac{x}{4}\to du=\frac{dx}{4}\to4du=dx\]\[\int_0}{dw:1326817852162:dw

suju101
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Pi ^{2}\div9{(65\Pi ^{2}/9)26)}\] i got this ans. s this correct??i

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0lol, I just derived tan^4(x/4) and got a spurious 1/4 so that cant be right

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm, im off by something

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0wolf agrees with turing

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0oh yeah, the 4 pops out to get rid of the 1/4 lol

shinigami1m
 3 years ago
Best ResponseYou've already chosen the best response.1derivative of (x/4) i think u miss it during derivative

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1yep, one comes out on top and bottom, so they cancel

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0a was using an abacus ;)

suju101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1326818150512:dw i did this process n got that ans

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1is the problem\[\int_{\frac{2\pi}{3}}^{\pi}\tan^3(\frac x4)\sec^2(\frac x4)dx\]?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1\[\int_{\frac{2\pi}{3}}^{\pi}\tan^3(\frac x4)\sec^2(\frac x4)dx\]\[u=\frac x4\to du=\frac{dx}{4}\to4du=dx\]so...\[\int_{\frac{2\pi}{3}}^{\pi}\tan^3(\frac x4)\sec^2(\frac x4)dx=4\int_{\frac{\pi}{6}}^{\frac{\pi}{4}}\tan^3u\sec^2udu=4(\frac14\tan^4(\frac x4))_{\frac{2\pi}{3}}^{\pi}\]\[=\tan^4(\frac x4)_{\frac{2\pi}{3}}^{\pi}\]evaluate...

robtobey
 3 years ago
Best ResponseYou've already chosen the best response.2\[\text{Tan}\left[\frac{\pi }{4}\right]^4\text{Tan}\left[\frac{\frac{2}{3}\pi }{4}\right]^4=\frac{8}{9} \]
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