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anonymous
 5 years ago
Can someone explain me the steps of solving integrals using partial fractions?
anonymous
 5 years ago
Can someone explain me the steps of solving integrals using partial fractions?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Should i give you am example?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the integration is usually the easy part. finding the decomposition is a pain often

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya i don't get the steps. my book didnt tell me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326817894193:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{(x2)(x3)}=\frac{a}{x2}+\frac{b}{x3}\] and you need a and b. we know that \[a(x3)+b(x2)=1\] so this is an easy one. since this equality has to be true for all values of x, it must be true if x = 2, so you get \[a(23)+b(22)=1\] \[a=1\] \[a=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol they got a diff answer is that ok?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How about using heavy side cover up for this one?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0repeat the process making x = 3, and you will find \[b=1\] so we have \[\frac{1}{(x2)(x3)}=\frac{1}{x2}+\frac{1}{x3}\] and now integrate term by term. now it is not ok

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0They got 1/3 and 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then maybe i made a mistake, let me write it out

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.0is that a 5 on the second set of parentheses?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL ya sorry abt that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh didnt even notce that sat

TuringTest
 5 years ago
Best ResponseYou've already chosen the best response.0sat has done it correctly for sure, just with the wrong number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no that is my fault, but idea is clear right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[a(x5)+b(x2)=1\] let \[x=2\] get \[3a=1,x=\frac{1}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ummmm so y did u chose the value 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am going to wager you can figure out why i picked 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and what i will pick next also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well cuz it is in the denomanator? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have this equality \[a(x5)+b(x2)=1\] and i am looking for a and b. so how can i find a easily?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0by eliminating one variable by making one part =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0zactly. so first we let x =2, and then we let x = 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok got that :D Thanks :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thought u guys started teaching today

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This one a is a simple one if I have a more difficult one I will be back :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with some practice you can do this: write \[\frac{1}{(x2)(x5)}=\frac{a}{x2}+\frac{b}{x5}\] now to find a, put your finger over the x  2 in the first expression, put x = 2 and get \[a=\frac{1}{23}=\frac{1}{3}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1its called office hours

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i really need to get back to work, but i have 30 emails to send out and got bored bored bored. later
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