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anonymous
 5 years ago
Determine the zeros of f(x) = x3 – 12x2 + 28x – 9
help please:)
anonymous
 5 years ago
Determine the zeros of f(x) = x3 – 12x2 + 28x – 9 help please:)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 12 28 9 0 < add these  x ) 1 < multiply these your "x" will be whatever you wanna test for a zero

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11,3,9 loos to be our options

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 12 28 9 0 3 27 3  3 ) 1 9 1 6: 6 is NOT a zero so "3" is out

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 12 28 9 0 3 45  3 ) 1 15 ...... this aint gonna zero out either

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11 12 28 9 0 9 27 9  9 ) 1 3 1 0 : x=9 works as a zero

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^2 3x +1 is a quadratic form now that can be done with the quad formula if need be

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If guess that one of the roots is rational, the possible roots from the rational root theorem are ±1 , ±3 , ±9. If I try x = 9, I find that f(9) = 0. x^3  12x^2 + 28x  9 = (x9)(x^2  3x + 1) Using the quadratic formula, the other 2 solutions are (3 ± sqrt(94))/2 = (3 ± sqrt(5))/2 Solutions to f(x) = 0 : 9 , (3 + sqrt(5))/2 , (3  sqrt(5))/2
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