anonymous
  • anonymous
solve x^2+ 7x+3=0
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
x^2+7 x+3 = 0 Subtract 3 from both sides: x^2+7 x = -3 Add 49/4 to both sides: x^2+7 x+49/4 = 37/4 Factor the left hand side: (x+7/2)^2 = 37/4 Take the square root of both sides: sqrt(x+7/2)^2 = sqrt(37)/2 Eliminate the absolute value: x+7/2 = -sqrt(37)/2 or x+7/2 = sqrt(37)/2 Subtract 7/2 from both sides: x = 1/2 (-7-sqrt(37)) or x+7/2 = sqrt(37)/2 Subtract 7/2 from both sides: x = 1/2 (-7-sqrt(37)) or x = 1/2 (-7+sqrt(37))
anonymous
  • anonymous
or use the quadratic formula
anonymous
  • anonymous
I have done- I got the answers -6.54 and -0.46. Are these right?

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anonymous
  • anonymous
yeah
anonymous
  • anonymous
oh thanks

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