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anonymous
 4 years ago
hey
im stuggling on a question, can someone please help
how do you get from
x(t) = e^(t/3)u(t)
to
X(s) = 3/(3s + 1)
x
anonymous
 4 years ago
hey im stuggling on a question, can someone please help how do you get from x(t) = e^(t/3)u(t) to X(s) = 3/(3s + 1) x

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but can not seem to get the answer. Help? I am really struggling x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large{L(e^{{\frac{t}{3}}}u(t))= \frac{1}{s+\frac{1}{3}}}= \frac{3}{3s+1}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1hmm, not to adept with these, but it looks like maybe: \[\frac{1}{3}tst=t(s+\frac{1}{3})\] how you get to Lanas I aint got no clue :) but afterwards you can simplify it by mutliplying at all by 3/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but u cant have t's in X(s)?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1right, which is the part im not to adept at ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How would you show this from first principles? x

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1pauls online notes has some good material

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not sure i did it right either, what i did was laplace(e^(t/3)) ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1http://tutorial.math.lamar.edu/Classes/DE/LaplaceDefinition.aspx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[e^{\alpha t}u(t)= \frac{1}{s+ \alpha}\]
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