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anonymous

  • 5 years ago

hey im stuggling on a question, can someone please help how do you get from x(t) = e^(-t/3)u(t) to X(s) = 3/(3s + 1) x

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  1. anonymous
    • 5 years ago
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    laplace transform?

  2. anonymous
    • 5 years ago
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    yeah but can not seem to get the answer. Help? I am really struggling x

  3. anonymous
    • 5 years ago
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    \[\large{L(e^{-{\frac{t}{3}}}u(t))= \frac{1}{s+\frac{1}{3}}}= \frac{3}{3s+1}\]

  4. amistre64
    • 5 years ago
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    hmm, not to adept with these, but it looks like maybe: \[-\frac{1}{3}t-st=-t(s+\frac{1}{3})\] how you get to Lanas I aint got no clue :) but afterwards you can simplify it by mutliplying at all by 3/3

  5. anonymous
    • 5 years ago
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    but u cant have t's in X(s)?

  6. amistre64
    • 5 years ago
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    right, which is the part im not to adept at ;)

  7. anonymous
    • 5 years ago
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    How would you show this from first principles? x

  8. amistre64
    • 5 years ago
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    ack!!

  9. amistre64
    • 5 years ago
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    pauls online notes has some good material

  10. anonymous
    • 5 years ago
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    im not sure i did it right either, what i did was laplace(e^(-t/3)) ...

  11. amistre64
    • 5 years ago
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    http://tutorial.math.lamar.edu/Classes/DE/LaplaceDefinition.aspx

  12. anonymous
    • 5 years ago
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    \[e^{-\alpha t}u(t)= \frac{1}{s+ \alpha}\]

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