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How do I integrate this dt=(a+bv)dv initial conditons are V=0 t=0 a and b are constants

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This is the original question. However, all I have done is divided dv on both sides.
t=av+b*(v^2)/2+c put t=0 and v=0 and find out c and put it and find out final ans
Did you just multiply the bracket by v? Also why did you divide by 2?

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Other answers:

i give the solution after integration
and integration of vdv=(v^2)/2
u got it or not reply fast
I'm an idiot, figured it out. Need more practice on simple indefinite integrals!

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