Write an equation for the parabola with a vertex at (2, -1) and y-intercept 5.

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Write an equation for the parabola with a vertex at (2, -1) and y-intercept 5.

Mathematics
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\[y = (x - 2)^2 -1\]
when x=0 that equals 3 tho, not 5
Messed up.. o_O

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Other answers:

Yeah..
figured//
gotta scale it right?
5 = a(-2)^2-1
its a good start tho, get the basic down and fidget with it
That was what the question asked, I am confused on how to calculate (a)
a is just a single unknown that can be algebraed into submission
add 1 and divide off the (-2)^2
My algebra teacher said the answer was \[3/2(x-2)^{2}\]
PLus 1 at the end sorry
almost, missing the -1 at the end tho
oh minus?
Ok so how did he get 3 halves?
5 = a(-2)^2 - 1 +1 +1 ---------------- 6 = a(4) /4 /4 --------- 6/4 = a
this is basic equation manipulations; you will need to become quite adept at it for further math skills
You put in the y intercept (5) in for x?
when x=0, y=5 so we zero out the x and replace y by 5
y = a(x-2)^2 - 1 5 = a(-2)^2 - 1
Is it also possible to substitute h and k as well instead?
h and k are your vertex elements
we plugged those in to determine "a"
oh ok i get it (hopefully) thank you
practice helps :)
Practise makes a man perfect. ;)

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