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you have to bring the 15 over to the other side first, THEN factor out the -16

oh you dont divide?

y - 15 = -16(t^2 - 3t) then...

i know that but i was just confused on why you don't divide?

ok i get it thank you!

You're welcome, if you need any more help just let me know.

you dont need to factor out all the numbers, just the t values will do

\[y=-16t^2+48t+15\]
\[y=(-16t^2+48t)+15\]
\[y=-16(t^2-3t)+15\]

the rest of it is completing the square on your t parts

did i doit right then?

yeah, it looks like you did it good

yay, ok so how would i turn this in to vertex form?

the final result IS vertex form

but i thought you would just get a "plus or minus this" answer

thats not vertex, that +- stuff is solving for the roots

vertex form is the equation using the vertex as a part of the equation

ik, i need to find h and k now

\[y=a(x-h)^2+k\]
\[y=-16(x-\frac{3}{2})+51\]

forgot to put my ^2 on there :/

yes i have this so far, so now would i square root everything?

WAIT IM DONE?

.... its always best that when you get to the end, to stop lol

oh i got negative 51...

help...