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anonymous
 4 years ago
the derivative of 2x^2
I need to know how to solve this using the derivative as a function... (using limits)
anonymous
 4 years ago
the derivative of 2x^2 I need to know how to solve this using the derivative as a function... (using limits)

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{h>0}\frac{f(x+h)f(x)}{h}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I already know that formula, i need to know how to use it....

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim\frac{2(x+h)^22x^2}{h}\] \[\lim\frac{2(x^2+2xh+h^2)2x^2}{h}\] \[\lim\frac{2x^2+4xh+2h^22x^2}{h}\] \[\lim\frac{\cancel{2x^2}+4xh+2h^2\cancel{2x^2}}{h}\] \[\lim\frac{4xh}{h}+\frac{2h^2}{h}\] \[\lim\frac{4x}{1}+\frac{2h}{1}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1if you know the formula, you know how to use it :/

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1now, when h=0; 4x+2h = 4x

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1when I first did these the "x" part of the function confused me a bit since they used x as part of the substituions

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1f(x+h) should be written better as say: f(a+h) maybe so that you know to replace "x" by whats in the ( )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, now i get it thanks alot

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1youre welcome, and good luck :)
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