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anonymous

  • 5 years ago

find all the roots of the equation x^3-3x^2+x-3=0

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  1. anonymous
    • 5 years ago
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    (x^3 - 3x^2) + (x-3) = 0 x^2(x - 3) + (x - 3) = 0 (x^2 + 1) (x - 3) = 0

  2. anonymous
    • 5 years ago
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    \[x^{3}-3x ^{2}+x-3=0\]

  3. anonymous
    • 5 years ago
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    i need all the roots of that

  4. LollyLau
    • 5 years ago
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    use moneybird's factored expression. either x^2+1 is zero or x-3 is 0.

  5. LollyLau
    • 5 years ago
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    -1, 1, 3

  6. anonymous
    • 5 years ago
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    x^2 + 1 = 0 x^2 = -1 no solution from this x - 3 = 0 x = 3

  7. LollyLau
    • 5 years ago
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    wait only one real solution?

  8. LollyLau
    • 5 years ago
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    3

  9. anonymous
    • 5 years ago
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    yeah you can't square root negative number. You get imaginary solutions as well

  10. anonymous
    • 5 years ago
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    i dont understnd ineed step by step

  11. LollyLau
    • 5 years ago
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    you factor the expression. you find the x's that make the expression zero

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