anonymous
  • anonymous
if rect(t) is function between -1/2 to 1/2 would rect(t/4) be stretched or shrunk?
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
why
anonymous
  • anonymous
lol btw what do you mean by stretch and shrunk?
Akshay_Budhkar
  • Akshay_Budhkar
ok if we take sinx and sinx/4 , it lies between -1 and 1

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Akshay_Budhkar
  • Akshay_Budhkar
so i beliueve it wont change
anonymous
  • anonymous
it would stretch
Akshay_Budhkar
  • Akshay_Budhkar
Why?
anonymous
  • anonymous
ishaan, that's what I am thinking too
anonymous
  • anonymous
u=t/4 -1/2
Akshay_Budhkar
  • Akshay_Budhkar
but u aren't provided with the function
asnaseer
  • asnaseer
It would stretch in the horizontal direction - not the vertical direction. @Akshay Budhkar is correct in that sense.
anonymous
  • anonymous
-2
anonymous
  • anonymous
I meant the period
Akshay_Budhkar
  • Akshay_Budhkar
-_-
Akshay_Budhkar
  • Akshay_Budhkar
the period stretches !
anonymous
  • anonymous
lol what else were you thinking? akshay
anonymous
  • anonymous
I think he was thinking amplitude
asnaseer
  • asnaseer
@imranmeah91 - there is nothing in the question to indicate that rect is a periodic function
anonymous
  • anonymous
oh amplitude "if rect(t) is function between -1/2 to 1/2 " i think this lines suggests it's periodic nature
anonymous
  • anonymous
line*
anonymous
  • anonymous
ok, horizontally stretched
asnaseer
  • asnaseer
|dw:1326849951351:dw| one possibility is it could asymptote towards the two limits
anonymous
  • anonymous
that's not rect(t) function
asnaseer
  • asnaseer
the only information given is that its range is between -1/2 and 1/2
asnaseer
  • asnaseer
unless you are saying that this is some well known function named "rect"
anonymous
  • anonymous
yes , there is http://en.wikipedia.org/wiki/Rectangular_function
asnaseer
  • asnaseer
that still does not look periodic to me. I think all we can say is that is would stretch it horizontally

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